No.
It is divisible by 10, but not by 235.
As 235 is ending by a 5 then it is divisible by 5 As 235 is not even it is not divisible by 2 As 2+3+5 is not divisible by 3, 235 is not divisible by 3 235/5 = 47 47 is prime so 235 = 5 * 47 and there's no other way to factorize it
235 and its multiples.
All multiples of 240 (which are infinite) are evenly divisible by 240.
The multiples of 235, which are infinite: 235, 470, 705, 940 +235 . . .
A number is divisible by 10 if its last digit is 0. To determine if a number is divisible by 235, it must be divisible by both 5 and 47 (since 235 = 5 × 47). Therefore, for a number to be divisible by both 235 and 10, it must end in 0 (for divisibility by 10) and be divisible by 47.
It is 240. It is 240. It is 240. It is 240.
To determine if 235 is divisible by 9, we sum its digits: 2 + 3 + 5 = 10. Since 10 is not divisible by 9, 235 is not divisible by 9. In order for a number to be divisible by 9, the sum of its digits must be divisible by 9.
240
It is 240
No.
No.