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Without an equality sign and not knowing the plus or minus values the information given can't be considered to be an equation.
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Isha sharma writes three liner equations in two variables as under 3x plus 2y equals 5 5x-7y equals -2 6x plus 4y equals 10which pairs has no solution?
There is no such pair. The solution to equation 1 and equation 2 is x = 1, y = 1. The solution to equation 2 and equation 3 is x = 1, y = 1. And the solution to equation 1 and equation 3 is any point on the line 3x + 2y = 5 - an infinite number of solutions. The fact that the determinant for equations 1 and 3 is zero (or that they are not independent) does not mean that there is no solution. It means that there is no UNIQUE solution. In this particular case, the two equations are equivalent and so have an infinite number of solutions.
Suppose x equals 5 is a solution to the equation 4zx plus 1 equals j where z and j are constants. Find a solution to the equation 8zx plus 5 equals 2j plus 3?
It is also x = 5 8zx + 5 = 2j + 3 → 8zx + 2 = 2j → 4zx + 1 = j Which is the first equation, which has a solution x = 5.
Which equation has a solution of -20?
10 (-2) 5 (-4)
Find two solutions for the equation y 3x - 5?
-2
What is the solution of the equation 5x 2?
Without an equality sign it is not an equation but if you mean: 5x=2 then x=2/5 or 0.4
Solution of equation 2x-5 equals 2-1?
2x -5 = 2-12x -5 +5= 2-1+52x = 62x/2 = 6/2x = 3
Isha sharma writes three liner equations in two variables as under 3x plus 2y equals 5 5x-7y equals -2 6x plus 4y equals 10which pairs has no solution?
There is no such pair. The solution to equation 1 and equation 2 is x = 1, y = 1. The solution to equation 2 and equation 3 is x = 1, y = 1. And the solution to equation 1 and equation 3 is any point on the line 3x + 2y = 5 - an infinite number of solutions. The fact that the determinant for equations 1 and 3 is zero (or that they are not independent) does not mean that there is no solution. It means that there is no UNIQUE solution. In this particular case, the two equations are equivalent and so have an infinite number of solutions.
Anyone who can simplify 2x2 9x - 5?
Presumably this is a quadratic equation question asking you to find the solution of 2x2+9x-5 = 0 First factorise the expression in the equation in order to find its solution. (2x-1)(x+5) = 0 Solution: x = 1/2 or x = -5
How many solutions does the equation have?
how many solutions does the equation have? 4x+1=5+2(2-4) a. one solution b. infinite solutions c. no solution
Suppose x equals 5 is a solution to the equation 4zx plus 1 equals j where z and j are constants. Find a solution to the equation 8zx plus 5 equals 2j plus 3?
It is also x = 5 8zx + 5 = 2j + 3 → 8zx + 2 = 2j → 4zx + 1 = j Which is the first equation, which has a solution x = 5.
Is 2 a solution of the inequality 2x 5 9?
2 is a solution of the equation, but not if it's an inequality.
What does a golden ratio mean in maths?
It is [1 + sqrt(5)]/2 It is the solution to the equation 1/x = x/(1+x)
Which equation has a solution of -20?
10 (-2) 5 (-4)
Find two solutions for the equation y 3x - 5?
-2
How many solutions are there in the equation 2x equals 10?
There is one solution. To find it, divide both sides of the equation by 2. This leaves you with x=5, where 5 is your solution.
Is 5 1 a solution of y -3x - 2?
I understand the equation to be y = -3x - 2 and the point to be (5,1). I substitute 1 for each appearance of y and 5 for each appearance of x: 1 = -3(5) - 2 = -15 - 2 = -17, which is not a true statement. Therefore, that is not a solution. To get a solution, set x=1, and calculate y by substituting this value (1) for x wherever it appears: y = -3(1) - 2 = -3 - 2 = -5. Therefore, (-5,1) is a solution. (I suspect that this is what you meant to put in the question.)
What is the solution of the equation 5x 2?
Without an equality sign it is not an equation but if you mean: 5x=2 then x=2/5 or 0.4
