I understand the equation to be y = -3x - 2 and the point to be (5,1).
I substitute 1 for each appearance of y and 5 for each appearance of x:
1 = -3(5) - 2 = -15 - 2 = -17, which is not a true statement. Therefore, that is not a solution.
To get a solution, set x=1, and calculate y by substituting this value (1) for x wherever it appears:
y = -3(1) - 2 = -3 - 2 = -5.
Therefore, (-5,1) is a solution. (I suspect that this is what you meant to put in the question.)
The value of x is the solution of 4 3x plus 5 17 is given as follows . 12 x + 5 =17. 12x =12. Hence , x=1. ThusThe value of x is the solution of 4 3x plus 5 17 is 1.
Let's try natural logs. 4e^(3X+1) = 10 divide both sides by 4 e^(3X+1) = 5/2 ln[e^(3X+1)] = ln(5/2) 3X+1 lne = ln(5/2) 3X+1 = ln(5/2)/lne ( natural log of e = 1, of course ) 3X + 1 = 5/2 subtract 1 from each side 3X = 3/2 divide each side by 3 X = 1/2
3x + 2y + 5 - 3 = 3x + 2y + 2 No further simplification is possible. This is an expression, not an equation so there cannot be a solution.
3x - y = -1 x = -2 3(-2) -y = -1 -6 - y = -1 -y = 5 y = -5
3x - 5 = 48 So 3x = 53 and x = 53/3 = 17.66...
The solution to 5 = 3x + 2 is found by first subtracting 2:3 = 3x.Then dividing by 3:x = 1.
Yes, it is.
x=1, y=5 is a legitimate answer.
If: y = 3x+4 and y = 2-7x Then: 3x+4 = 2-7x So: 3x+7x = 2-4 => 10x = -2 => x = -1/5 By substitution: y = 17/5 Solution: x = -1/5 and y = 17/5
3x+5 Solution- 3x+5=0 3x= (-5) x= (-5)/3
5=3x+2 3x+2-2=5-2 3x=3 ------ 3 x=1
2x+3 = 3x+5 2x-3x = 5-3 -x = 2 x = -2
3x-5=3x+5 There is no solution.
3x+5=2, 3x=2-5 (sign changes) 3x=-3 x=-1
-2
2(x+5) =3X+1 => 2x+10-3x-1=0. => -x+9 => x=9
The value of x is the solution of 4 3x plus 5 17 is given as follows . 12 x + 5 =17. 12x =12. Hence , x=1. ThusThe value of x is the solution of 4 3x plus 5 17 is 1.