-2
The equation (3x + 8 = 3x - 5) has no solutions because when you simplify it, you end up with (8 = -5), which is a contradiction. This means there are no values of (x) that can satisfy the equation, indicating that the two sides are never equal. Thus, the equation is inconsistent and has no solution.
The equation (3x + 8 = 3x - 5) has no solutions because when you simplify it, you subtract (3x) from both sides, resulting in (8 = -5). This statement is false, as 8 does not equal -5. Since the equation leads to a contradiction, it indicates that there are no values of (x) that can satisfy it. Thus, the equation has no solutions.
The equation (3x + 8 = 3x - 5) has no solutions because when we attempt to isolate (x), we end up with a contradiction. Subtracting (3x) from both sides results in (8 = -5), which is not true. Since there are no values of (x) that can satisfy this equation, it has no solutions.
There are none because without an equality sign it can not be considered to be an equation and the + or - values of 3x and 10 are not given
An algebraic equation with an infinite number of solutions
The equation (3x + 8 = 3x - 5) has no solutions because when you simplify it, you subtract (3x) from both sides, resulting in (8 = -5). This statement is false, as 8 does not equal -5. Since the equation leads to a contradiction, it indicates that there are no values of (x) that can satisfy it. Thus, the equation has no solutions.
The equation (3x + 8 = 3x - 5) has no solutions because when we attempt to isolate (x), we end up with a contradiction. Subtracting (3x) from both sides results in (8 = -5), which is not true. Since there are no values of (x) that can satisfy this equation, it has no solutions.
That's not an equation - it doesn't have an equal sign. Assuming you mean 2x2 - 3x - 90 = 0, you can find the solution, or usually the two solutions, of such equations with the quadratic formula. In this case, replace a = 2, b = -3, c = -90.
There are none because without an equality sign it can not be considered to be an equation and the + or - values of 3x and 10 are not given
If you mean: 3x^2+12x+12 = 0 then it has two equal solutions of -2
An algebraic equation with an infinite number of solutions
How many solutions are there to the equation below? 3x-10(x+2) = 13-7x 0
Answer: no solution3x - 2 = 3x -53x - 3x - 2 = 3x - 3x - 5 (Subtract 3x from each side.)-2 = -5 Huh??When you are solving an equation, and the variable disappears, there are two possibilities:If you are left with a true statement (such as 2 = 2), then the equation is an identity, and any value of x will satisfy the equation. The number of solutions is infinite.If you are left with a false statement, as in this case, no value of x will satisfy the equation. There is no solution.
There are two terms: 3x, -2b. Yeah, two terms. But where is the equation?
One.
None because without an equal sign it's not an equation
The answer has been right under your nose all this time.The equation of y equals -3x isy = -3x