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How many even 4 digit numbers can you form from the digits 1 2 3 and 5?
In order for the number to be even, the '2' must be the last digit. So we only need tofigure out how many ways there are to arrange the 1, 3, and 5 in the first 3 places.The first place can be any one of 3 digits. For each of those ...The second place can be either one of the 2 remaining digits.And then the third place has to be the only digit that's left.So there are (3 x 2) = 6 ways to arrange 1, 3, and 5 in the first 3 places.That means only 6 even 4-digit numbers can be made from the digits 1, 2, 3, and 5.And here they are:1 3 5 21 5 3 23 1 5 23 5 1 25 1 3 25 3 1 2
What is the ratio of even numbers to odd p.s the numbers are 1 - 9?
if the numbers are from 1 - 9 then the ratio of even to odd is 4:5 (2, 4, 6 & 8 are even, 1, 3, 5, 7 & 9 are odd)
Is 794 odd or even?
Numbers that end with 0, 2, 4, 6, or 8 are even. Numbers that end with 1, 3, 5, 7, or 9 are odd.Numbers that end with 0, 2, 4, 6, or 8 are even. Numbers that end with 1, 3, 5, 7, or 9 are odd.Numbers that end with 0, 2, 4, 6, or 8 are even. Numbers that end with 1, 3, 5, 7, or 9 are odd.Numbers that end with 0, 2, 4, 6, or 8 are even. Numbers that end with 1, 3, 5, 7, or 9 are odd.
Two spinners each marked 1-5 are spun together how many ways are there of scoring a total that is an even number?
6
How do you rationalize the denominator in this expression 5 divided by square root of 3 minus 1?
5/(√3 - 1)= 5(√3 + 1)/(√3 - 1)(√3 + 1)= (5√3 + 5)/[(√3)2 - 12)= (5√3 + 5)/(3 - 1)= 5√3 + 5)/2= 5√3/2 + 1/2
How many even number from 1 through 150 are multiples of both 3 and 5?
to be an even multiple of 3 and 5 means it has to be a multiple of 2x3x5 = 30 answer is 5 numbers: 30, 60, 90, 120, 150
What is an even number that is written using 1 3 5 7 and 9?
there are none
Is 247 an even or odd?
odd endings 1 3 5 7 9
What is 3 digits plus 3 digits and equals 3 digits only using numbers 1 through 9 without carrying a number?
There is no solution to this problem. If each digit can be used once only then we have 5 odd numbered digits (1,3,5,7,9) and 4 even numbered digits (2,4,6,8). To create the two numbers that are added together requires the following combinations of digits. 5 Odd & 1 Even ....when added these will generate 2 Even digits & 1 Odd digit but the remaining digits are 3 Even. 4 Odd & 2 Even. These will generate 3 Even digits OR 1 Even digit & 2 Odd digits but the remaining digits are 1 Odd & 2 Even. 3 Odd & 3 Even. These generate 3 Odd digits OR 2 Even & 1 Odd digits but the remaining digits are 2 Odd & 1 Even. 2 Odd & 4 Even. These generate 3 Even digits OR 2 Odd & 1 Even digits but the remaining digits are 3 Odd & no Even.
What is the subset of set A12345?
There are 64 subsets, and they are:{}, {A}, {1}, {2}, {3}, {4}, {5}, {A,1}, {A,2}, {A,3}, {A,4}, {A,5}, {1,2}, {1,3}, {1,4}, {1,5}, {2,3}, {2,4}, {2,5}, {3,4}, {3, 5}, {4,5}, {A, 1, 2}, {A, 1, 3}, {A, 1, 4}, {A, 1, 5}, {A, 2, 3}, {A, 2, 4}, {A, 2, 5}, {A, 3, 4}, {A, 3, 5}, {A, 4, 5}, {1, 2, 3}, {1, 2, 4}, {1, 2, 5}, {1, 3, 4}, {1, 3, 5}, {1, 4, 5}, {2, 3, 4}, {2, 3, 5}, {2, 4, 5}, {3, 4, 5}, {A, 1, 2, 3}, {A, 1, 2, 4}, {A, 1, 2, 5}, {A, 1, 3, 4}, {A, 1, 3, 5}, {A, 1, 4, 5}, {A, 2, 3, 4}, {A, 2, 3, 5}, {A, 2, 4, 5}, {A, 3, 4, 5}, {1, 2, 3, 4}, {1, 2, 3, 5}, {1, 2, 4, 5}, {1, 3, 4, 5}, {2, 3, 4, 5}, {A, 1, 2, 3, 4}, {A, 1, 2, 3, 5}, {A, 1, 2, 4, 5}, {A, 1, 3, 4, 5}, {A, 2, 3, 4, 5}, {1, 2, 3, 4, 5} {A, 1, 2, 3,,4, 5} .
What is seven minus one and three fifth?
(3 1/5) - (1 3/5) : If we borrow 1 from 3, then 3 1/5 becomes 2 6/5 [1 = 5/5, and 1/5+5/5 = 6/5]. Now can subtract 3/5 from 6/5, and subtract 1 from 2:6/5 - 3/5 = 3/5. 2-1 = 1. So the answer is 1 3/5.
What is the minimum number of players required to play basketball?
5 on 5 is official and you could do anything else in street like 3 on 3, 4 on 4, 1 on 1, or even 3 on 2 and so on.
