no
Yes. 1 + 0 + 0 + 8 + 0 = 9 which is 9, so 10080 is divisible by 9.
not divisible by 9.but it is divisible by 4.
NO. 1110 is not divisible by 9. A number is divisible by 9 if the sum of its digits is divisible by 9. 1110 = 1 + 1 + 1 + 0 = 3 (3 is not divisible by 9, thus, 1110 is not divisible by 9.)
Yes, 100 is divisible by 3. To determine if a number is divisible by 3, you can sum its digits. The sum of the digits in 100 is 1 + 0 + 0 = 1, which is not divisible by 3. Therefore, 100 is not divisible by 3.
of course all numbers are divisible by 1 expect 0 and numbers that have decimals
1, 2, 0, 3 and 8 are not divisible by 4 and/or 9. Neither is 12038.
The sum of its digits is 1+2+0 = 3 which is divisible by 3. So 120 is divisible by 3. The number 120 ends in a 0 and so it is divisible by 5.
If you multiply 417 by any integer (0, 1, 2, 3, -1, -2, -3, etc.), you will get a number that is divisible by 417.If you multiply 417 by any integer (0, 1, 2, 3, -1, -2, -3, etc.), you will get a number that is divisible by 417.If you multiply 417 by any integer (0, 1, 2, 3, -1, -2, -3, etc.), you will get a number that is divisible by 417.If you multiply 417 by any integer (0, 1, 2, 3, -1, -2, -3, etc.), you will get a number that is divisible by 417.
to be divisible by 5 the last digit of the number has to be 0 or 5
2390 is not divisible by 3 but is divisible by 5. 2 + 3 + 9 + 0 = 14; 1 + 4 = 5: 5 is not divisible by 3, so 14 is not divisible by 3, so 2390 is not divisible by 3. 2390 ends with a 0, so 2390 is divisible by 5.
Check your divisibility rules: 2: One's digit is an even number YES 3: The sum of the digits is divisible by 3 NO: 7 + 1 + 0 = 8 which is not divisible by 3 5: One's digit is a 5 or a 0 YES 9: The sum of the digits is divisible by 9 NO: 7 + 1 + 0 = 8 which is not divisible by 9 10: One's digit is a 0 YES
Yes, it is. The digital root of 1430061, that is, the sum of all its digits is 1+4+3+0+0+6+1 = 15 The digital root of 15 is 1+5 = 6 which is divisible by 3. So 1430061 is divisible by 3.