Best Answer

21789 is divisible by 1, 3, 9, 27, 81, 269, 807, 2421, 7263, 21789

Q: Is 21789 divisible by 2 3 5 9 or?

Write your answer...

Submit

Still have questions?

Continue Learning about Math & Arithmetic

It is divisible by 2 and 3. It isn't divisible by 5 and 10.

Is 5225 divisible by 3? A number is divisible by 3, if the sum of its digits is evenly divisible by 3. 5 + 2 + 2 + 5 = 14. Since 14 is not divisible by 3, neither is 5225.

30 is divisible by, and is the least common multiple of, 2, 3, and 5.

One of the infinitely many integers divisible by 2, 3 and 5 is 3000.

2390 is not divisible by 3 but is divisible by 5. 2 + 3 + 9 + 0 = 14; 1 + 4 = 5: 5 is not divisible by 3, so 14 is not divisible by 3, so 2390 is not divisible by 3. 2390 ends with a 0, so 2390 is divisible by 5.

Related questions

yep it is because 2 is divisible by 2 and 3 is divisible by 3 and 0 is divisible by 5 have fun suckers!

It is divisible by 2 and 3. It isn't divisible by 5 and 10.

It is divisible by 2 & 3. It is not divisible by 5, 9 & 10. 534 is even → divisible by 2 5 + 3 + 4 = 12 → divisible by 3 534 does not end in 0 or 5 → not divisible by 5 5 + 3 + 4 = 12 → not divisible by 9 534 does not end in 0 → not divisible by 10

Yes, it is divisible by 2, 3 and 9, but is not exactly divisible by 5 or 10.

Is 5225 divisible by 3? A number is divisible by 3, if the sum of its digits is evenly divisible by 3. 5 + 2 + 2 + 5 = 14. Since 14 is not divisible by 3, neither is 5225.

20 is divisible by 2, 5 and 10. It is not exactly divisible by 3 or 9.

The smallest number divisible by 2 3 5 is 30.

It is divisible by 2, 5 and 10, but not 3 and 9.

30 is divisible by, and is the least common multiple of, 2, 3, and 5.

One of the infinitely many integers divisible by 2, 3 and 5 is 3000.

2390 is not divisible by 3 but is divisible by 5. 2 + 3 + 9 + 0 = 14; 1 + 4 = 5: 5 is not divisible by 3, so 14 is not divisible by 3, so 2390 is not divisible by 3. 2390 ends with a 0, so 2390 is divisible by 5.

Last digit (0) is even, so it is divisible by 2 4 + 3 + 2 + 0 = 9 which is divisible by 3, so it is divisible by 3 last digit is 0 or 5, so it is divisible by 5 4 + 3 + 2 + 0 = 9 which is divisible by 9, so it is divisible by 9 last digit is 0, so it is divisible by 10 → 4320 is divisible by all the numbers 2, 3, 5, 9, 10