Q: Is 21789 divisible by 2 3 5 9 or?

Write your answer...

Submit

Still have questions?

Continue Learning about Math & Arithmetic

It is divisible by 2 and 3. It isn't divisible by 5 and 10.

Is 5225 divisible by 3? A number is divisible by 3, if the sum of its digits is evenly divisible by 3. 5 + 2 + 2 + 5 = 14. Since 14 is not divisible by 3, neither is 5225.

2390 is not divisible by 3 but is divisible by 5. 2 + 3 + 9 + 0 = 14; 1 + 4 = 5: 5 is not divisible by 3, so 14 is not divisible by 3, so 2390 is not divisible by 3. 2390 ends with a 0, so 2390 is divisible by 5.

One of the infinitely many integers divisible by 2, 3 and 5 is 3000.

30 is divisible by, and is the least common multiple of, 2, 3, and 5.

Related questions

yep it is because 2 is divisible by 2 and 3 is divisible by 3 and 0 is divisible by 5 have fun suckers!

It is divisible by 2 and 3. It isn't divisible by 5 and 10.

It is divisible by 2 & 3. It is not divisible by 5, 9 & 10. 534 is even → divisible by 2 5 + 3 + 4 = 12 → divisible by 3 534 does not end in 0 or 5 → not divisible by 5 5 + 3 + 4 = 12 → not divisible by 9 534 does not end in 0 → not divisible by 10

Yes, it is divisible by 2, 3 and 9, but is not exactly divisible by 5 or 10.

Is 5225 divisible by 3? A number is divisible by 3, if the sum of its digits is evenly divisible by 3. 5 + 2 + 2 + 5 = 14. Since 14 is not divisible by 3, neither is 5225.

20 is divisible by 2, 5 and 10. It is not exactly divisible by 3 or 9.

The smallest number divisible by 2 3 5 is 30.

2390 is not divisible by 3 but is divisible by 5. 2 + 3 + 9 + 0 = 14; 1 + 4 = 5: 5 is not divisible by 3, so 14 is not divisible by 3, so 2390 is not divisible by 3. 2390 ends with a 0, so 2390 is divisible by 5.

It is divisible by 2, 5 and 10, but not 3 and 9.

30 is divisible by, and is the least common multiple of, 2, 3, and 5.

One of the infinitely many integers divisible by 2, 3 and 5 is 3000.

Last digit (0) is even, so it is divisible by 2 4 + 3 + 2 + 0 = 9 which is divisible by 3, so it is divisible by 3 last digit is 0 or 5, so it is divisible by 5 4 + 3 + 2 + 0 = 9 which is divisible by 9, so it is divisible by 9 last digit is 0, so it is divisible by 10 → 4320 is divisible by all the numbers 2, 3, 5, 9, 10