Best Answer

21 is not divisible by 2 nor 5, but it is divisible by 3.

To be divisible by 2 the last digit must be even (one of {0, 2, 4, 6, 8}; the last digit 1 is not one of these, thus 21 is not divisible by 2

To be divisible by 3 sum the digits and if this total is divisible by 3, then so is the original number; the test can be repeated on the sum, so by repeatedly summing the digits of the totals until a single digit remains only if that single digit is 3, 6 or 9 is the original number divisible by 3. 21 → 2 + 1 = 3 which is divisible by 3 so 21 is divisible by 3.

To be divisible by 5, the last digit must be 0 or 5. The last digit of 21 is 1 which is not 0 nor 5, thus 21 is not divisible by 5.

🙏

🤨

😮

Q: Is 21 divisible by 2 3 or 5?

Write your answer...

Submit

Related questions

yep it is because 2 is divisible by 2 and 3 is divisible by 3 and 0 is divisible by 5 have fun suckers!

It is divisible by 2 and 3. It isn't divisible by 5 and 10.

It is divisible by 2 & 3. It is not divisible by 5, 9 & 10. 534 is even → divisible by 2 5 + 3 + 4 = 12 → divisible by 3 534 does not end in 0 or 5 → not divisible by 5 5 + 3 + 4 = 12 → not divisible by 9 534 does not end in 0 → not divisible by 10

If its divisible by 5 AND 2 it must be divisible by 10 So you just have to pick the only number between 21 and 39 that's divisible by 10

it cannot be divisable by 5 and 9 but it can be divisable by 2,3,4,6,41,28,and 21

Is 5225 divisible by 3? A number is divisible by 3, if the sum of its digits is evenly divisible by 3. 5 + 2 + 2 + 5 = 14. Since 14 is not divisible by 3, neither is 5225.

Yes, it is divisible by 2, 3 and 9, but is not exactly divisible by 5 or 10.

yeah3 9 15 21 27 and so on(every other multiple of three)But if you have a large number, like 755253, and don't have a calculator handy, then use sum of digits to determine if divisible by 3.Then if the number is divisible by 3 and divisible by 2, then it is also divisible by 6.So in this case: 7 + 5 + 5 + 2 + 5 + 3 = 27, which is divisible by 3, but the original number is odd, so the number is not divisible by 6.

20 is divisible by 2, 5 and 10. It is not exactly divisible by 3 or 9.

The smallest number divisible by 2 3 5 is 30.

2390 is not divisible by 3 but is divisible by 5. 2 + 3 + 9 + 0 = 14; 1 + 4 = 5: 5 is not divisible by 3, so 14 is not divisible by 3, so 2390 is not divisible by 3. 2390 ends with a 0, so 2390 is divisible by 5.

It is divisible by 2, 5 and 10, but not 3 and 9.

30 is divisible by, and is the least common multiple of, 2, 3, and 5.

One of the infinitely many integers divisible by 2, 3 and 5 is 3000.

Last digit (0) is even, so it is divisible by 2 4 + 3 + 2 + 0 = 9 which is divisible by 3, so it is divisible by 3 last digit is 0 or 5, so it is divisible by 5 4 + 3 + 2 + 0 = 9 which is divisible by 9, so it is divisible by 9 last digit is 0, so it is divisible by 10 → 4320 is divisible by all the numbers 2, 3, 5, 9, 10

It is divisible by 2 and 5

29,178 is divisible by 2, 3 and 9, not by 5 or 10.

It is evenly divisible by 2 and by 3.

As 235 is ending by a 5 then it is divisible by 5 As 235 is not even it is not divisible by 2 As 2+3+5 is not divisible by 3, 235 is not divisible by 3 235/5 = 47 47 is prime so 235 = 5 * 47 and there's no other way to factorize it

It is divisible by 2, 5 and 10 but not the rest.

A Harshad number is a positive integer which is is divisible by the sum of its digits. There are many Harshad numbers, for example, 1, 2, 3, 4, 5, 6, 7, 8, 9, 18 (1 + 8 = 9 and 18 is divisible by 9), 21 (2 + 1 = 3 and 21 is divisible by 3), and 24 ( 2 + 4 = 6 and 24 is divisible by 6).

2 and 3, yes. 5, no.

It is divisible only by 3; It is not divisible by 2, 4, 5, 6, 9, 10. 17211 is odd, so not divisible by 2, 4, 6 nor 10. 1 + 7 + 2 + 1 + 1 = 12 which is divisible by 3, so 17211 is divisible by 3, but 12 is not divisible by 9, so 17211 is not divisible by 9. 17211 does not end in 5 or 0 so not divisible by 5

475 is evenly divisible by 5, but not by 2, 3, 4, or 10.

9 is divisible by 3 10 is divisible by 2, 5 and 10. Everything else, no.