Yes, but not evenly, quotient is 24 and remainder is 6
Oh, dude, to find out how many integers from 1 to 2000 are divisible by 9, you just need to divide 2000 by 9 and see how many times it goes in evenly. So, 2000 divided by 9 is like 222 with a remainder, but we only care about the whole number part, which is 222. So, there are 222 integers from 1 to 2000 that are divisible by 9.
One easy way to check is sum of digits. 819: 8+1+9 = 18. 18 is a multiple of 3. 819 is divisible by 3. 440: 4+4+0 = 8. Not a multiple of 3. 440 is not divisible by 3. 222: 2+2+2 = 6. 6 is a multiple of 3. 222 is divisible by 3.
It is divisible by 1, 2, 3, 6, 37, 74, 111 and 222.
Yes, of course it is.
Yes because 222/3 = 74 --------------------------------------- (Better Example) Look at 222/3 Factors 222 and 3 have greatest common factor (GCF) of 3. Reducing fraction. It becomes 74/1 --------------------------------------------------------- Look at 74/1 Remove extraneous '1' from product 1/1 It becomes [74] Result: 74
222
NO. 1110 is not divisible by 9. A number is divisible by 9 if the sum of its digits is divisible by 9. 1110 = 1 + 1 + 1 + 0 = 3 (3 is not divisible by 9, thus, 1110 is not divisible by 9.)
81: 8 + 1 = 9 which is divisible by 9, so 81 is divisible by 9 162: 1 + 6 + 2 = 9 which is divisible by 9, so 162 is divisible by 9 199: 1 + 9 + 9 = 19 → 1 + 9 = 10 → 1 + 0 = 1 which is not divisible by 9, so 199 is not divisible by 9. 1125: 1 + 1 + 2 + 5 = 9 which is divisible by 9, so 1125 is divisible by 9. So 199 is the only one not divisible by 9.
All multiples of 666, which is an infinite number.
There are 200 of them. Starting with 45*23 = 1035 and all the multiples of 45 up to 45*222 = 9990.
All numbers divisible by 3 are NOT divisible by 9. As an example, 6, which is divisible by 3, is not divisible by 9. However, all numbers divisible by 9 are also divisible by 3 because 9 is divisible by 3.
No it is not divisible by 9 .