Q: Is 243 divisible by 3 and 9?

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Everything's divisible. 243 is divisible by 1, 3, 9, 27, 81 and 243.

1, 3, 9, 27, 81 and 243.

Yes, 243 is divisible by 1, 3, 9, 27, 81, 243.

3 and 9, yes. 2 and 8, no.

Yes because: 243/9 = 27

it's only divisible by 3 243 divided by 3 is 81

729 is divisible by 1, 3, 9, 27, 81, 243, 729.

Yes, 243 divided by 3 equals 81.

3, 9, 27, 41, 81, 123, 243, 369, 1107, 3321.

numbers are divisible by 243 are the multiples of 243 like 243, 486, 729, 972,...

3 3^5 = 243 (3 x 3) x (3 x 3) x 3 = 243 9 x 9 x 3 = 243 81 x 3 = 243

1, 3, 9, 27, 81, 243, -1, -3, -9, -27, -81, -243

All numbers divisible by 3 are NOT divisible by 9. As an example, 6, which is divisible by 3, is not divisible by 9. However, all numbers divisible by 9 are also divisible by 3 because 9 is divisible by 3.

Multiples of 9 and 6 are also divisible by three, the reverse is not true. 15 is divisible by 3, but not 6 or 9. 27 is divisible by 3 and 9, but not 6. 12 is divisible by 3 and 6, but not 9. 54 is divisible by 3, 6 and 9.

9 is divisible by both 3 and 9

It has more than two factors.

All factors of 243 are: -243, -81, -27, -9, -3, -1, 1, 3, 9, 27, 81, and 243.

234 ========== or 243

The positive integer factors of 243 are 1, 3, 9, 27, 81, and 243 The factor pairs of 243 are (1, 243), (3, 81), and (9, 27).

Three is divisible by 3 and 9.

None, because 9 is divisible by 3.

3 yes, 9, no.

If a number is not divisible by 3 then it is not divisible by 9.

All numbers divisible by 9 are divisible by 3; since 9 = 3 x 3 all multiples of 9 are also multiples of 3. However, all numbers divisible by 3 are not divisible by 9, eg 6 = 2 x 3 but 6 is not divisible by 9 (since 6 is not a multiple of 9) - it only takes one counter example to disprove a theory.

NO. 1110 is not divisible by 9. A number is divisible by 9 if the sum of its digits is divisible by 9. 1110 = 1 + 1 + 1 + 0 = 3 (3 is not divisible by 9, thus, 1110 is not divisible by 9.)