Well, isn't that just a happy little question! Yes, 243 is divisible by 3. You see, when you add up all the digits in 243 (2 + 4 + 3), you get 9, which is a multiple of 3. So you can easily divide 243 by 3 and create a beautiful, harmonious result.
To make 243 divisible by 10, we need to find the nearest multiple of 10. The nearest multiple of 10 less than 243 is 240. To make 243 divisible by 10, we need to add 240 + 3, which equals 243. Therefore, we need to add 3 to 243 to make it divisible by 10.
3 and 9, yes. 2 and 8, no.
Yes because: 243/9 = 27
Not without a remainder: 731 ÷ 3 = 243 remainder 2
Well, honey, if you want to make 243 divisible by 10, you need to add 7 to it. Why 7, you ask? Because 243 + 7 = 250, and 250 is divisible by 10. So, go ahead and sprinkle that 7 on top like the cherry on a sundae.
Everything's divisible. 243 is divisible by 1, 3, 9, 27, 81 and 243.
it's only divisible by 3 243 divided by 3 is 81
1, 3, 9, 27, 81 and 243.
Yes
Yes, 243 is divisible by 1, 3, 9, 27, 81, 243.
numbers are divisible by 243 are the multiples of 243 like 243, 486, 729, 972,...
To make 243 divisible by 10, we need to find the nearest multiple of 10. The nearest multiple of 10 less than 243 is 240. To make 243 divisible by 10, we need to add 240 + 3, which equals 243. Therefore, we need to add 3 to 243 to make it divisible by 10.
It has more than two factors.
No, it's not. 243 is divisible by 3 and 81. To be prime, a number's only factors must be 1 and itself.
3 and 9, yes. 2 and 8, no.
729 is divisible by 1, 3, 9, 27, 81, 243, 729.
Yes because: 243/9 = 27