2, 82, 4, 41. 164 = 2 x 2 x 41
The Least Common Multiple (LCM) for 41 2 is 82.
The Least Common Multiple (LCM) of 4 and 41 is 164.
No. 41 is not a mutiple of 4. There are a few whole numbers, not many, of which 41 is a mutiple, but 4 is not one of them. The only ones that meet the requirement are ' 1 ' and ' 41 '.
164
41 - 9, D16
The number is a multiple of 2 and 41 at the same time
Any multiple of 4 is also a multiple of 2.
No, but vice versa holds true. Case and point: 6 is a multiple of 2, but not a multiple of 4. 8 is a multiple of 4, and is a multiple of 2. Because a factor of 4 is 2, every multiple of 4 is also a multiple of 2. But since 4 is not a factor of 2, rather, only half of it, only half of the multiples of 2 will be multiples of 4.
4 4 is the second multiple of 2 and the first multiple of itself, so it is the LCM of 2 and 4.
x² - 4x = 41 → x² -4x - 41 = 0 Using the quadratic formula: x = (-b ± √(b² - 4ac))/(2a) → x = (4 ± √(4² - 4×1×-41)/(2×1) → x = (4 ± √(4(4+41)))/2 → x = (4 ± 2√45)/2 → x = 2 ± √45 → x = 2 + √45 (≈ 8.708) or x = 2 - √45 (≈ -4.708)
1. a is a factor of b. 2. c = 2b = 4a, thus b = 2a and c = 4a. 3. d is prime between 10 & 20. 4. a + b + c + d = 41. Therefore: a + 2a + 4a + d = 41 7a + d = 41 d = 41 - 7a The only integer value for awhich results in d being a prime between 10 and 20 is where a = 4. If a = 4 then b = 2a = 4 * 2 = 8 c = 4a = 4 * 4 = 16 d = 41 - (7*4) = 41 - 28 = 13 The numbers are thus 4,8,16 and 13.