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What else can I help you with?
How do factor c2-1c-12?
(c-4) x (c+3)
Which binomial is a factor of c squared minus 12c plus 32?
It is: (c-4)(c-8) when factored
Factor c2 plus 4c plus 4?
(c + 2)(c + 2) or (c + 2)2
Factor the following trinomials c squared plus 4c plus 4?
c2 + 4c + 4 =(c + 2) (c + 2)= (c + 2)2
What will be the remainder when c2 - 4 is divided by c plus 2?
c2 - 4 = (c+2)*(c-2) So, dividing by (c+2) leaves the other factor: (c-2)
Factor c squared plus 9d squared - 4?
13
Factor c squared - 6cd plus 9d squared - 4?
c2 - 6cd + 9d2 - 4 The first three terms are a complete square = (c - 3d)2 - 4 Difference of two squares = (c - 3d + 2)(c - 3d - 2)
Factor 9c3-12c2 plus 18c-24?
3(3c - 4)(c^2 + 2)
How do you solve this 4c2 plus 12c-72?
If you factor this you would first factor out a common multiple4(c^2+3c-18)4(c+6)(c-3)The 6 and -3 were arrived by thinking,"What adds together to get +3 and mu;tiplies to get -18?"
What is the greatest common factor of the products ab ac and bc if b is a factor of c?
The answer depends on whether or not a is a factor of c.
How can you factor a polynomial in standard form completely?
You can factor a polynomial using one of these steps: 1. Factor out the greatest common monomial factor. 2. Look for a difference of two squares or a perfect square trinomial. 3. Factor polynomials in the form ax^2+bx+c into a product of binomials. 4. Factor a polynomial with 4 terms by grouping.
A B C Has coordinates of A(6 7) B(4 2) and C(0 7). Find the coordinates of its image after a dilation centered at the origin with a scale factor of 2.?
To find the image of points A, B, and C after a dilation centered at the origin with a scale factor of 2, you multiply each coordinate by 2. The new coordinates are A'(12, 14), B'(8, 4), and C'(0, 14). Thus, the images of the points after dilation are A'(12, 14), B'(8, 4), and C'(0, 14).
