Only if C is a multiple of 4.
(c-4) x (c+3)
(c + 2)(c + 2) or (c + 2)2
It is: (c-4)(c-8) when factored
c2 + 4c + 4 =(c + 2) (c + 2)= (c + 2)2
c2 - 4 = (c+2)*(c-2) So, dividing by (c+2) leaves the other factor: (c-2)
13
c2 - 6cd + 9d2 - 4 The first three terms are a complete square = (c - 3d)2 - 4 Difference of two squares = (c - 3d + 2)(c - 3d - 2)
3(3c - 4)(c^2 + 2)
The answer depends on whether or not a is a factor of c.
If you factor this you would first factor out a common multiple4(c^2+3c-18)4(c+6)(c-3)The 6 and -3 were arrived by thinking,"What adds together to get +3 and mu;tiplies to get -18?"
You can factor a polynomial using one of these steps: 1. Factor out the greatest common monomial factor. 2. Look for a difference of two squares or a perfect square trinomial. 3. Factor polynomials in the form ax^2+bx+c into a product of binomials. 4. Factor a polynomial with 4 terms by grouping.
(c - d)(c + d)