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A number is divisible by 3 if the sum of its digits is divisible by 3. The sum of the digits of 60 is 6 + 0 = 6, which is divisible by 3, so, yes, 60 is divisible by 3.

60 ÷ 3 = 20

60 ÷ 3 = 20

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0No. divisible by 3 4 5 is 60

42, 48, 54, and 60 is. -- If it's 'even' then it must also be divisible by 2 . -- If it's divisible by 3 and also by 2, then it must be divisible by 6 . -- The multiples of 6 between 40 and 60 are 42, 48, 54, and 60 .

Depends if you are talking about divisible with whole numbers then no. For example 60/20=3 and 60/40=1.5.

Any multiple of 60 is divisible by 3, 4, and 5. (Also by 1, 2, 6, 10, 12, 15, 20, 30, and 60.)

60 is divisible by 3, 4, 5, and 6.

Because 60 is divisible by numbers other than 1 and 60. 60 is divisible by 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60

60/9 = 20/3 since both 60 and 9 are divisible by 3

LCM(5, 3, 4) = 60

Nope. 3 x 100 = 300 and 3 x 20 = 60 and 60 - 3 = 57 so no.

60/4 = 15 Therefore, 60 is divisible by 4.

6, 9, 12, 30, 60, 90, 360, 690, 930, or (162,591). Here's a secret: If the sum of a number's digits is divisible by 3, then the number is divisible by 3. That's how you can tell quickly that 162,591 is divisible by 3.

numbers divisible by 60 are the multiples of 60: 60, 120, 180,240,400, 360, 420,...

Any multiple of 60

They are both divisible by 3, 5 and 15.

The quotient of 180/3 is 60. So yes it is divisible by three. All numbers are divisible by three, but division is not a closed operation until you use the rational numbers.

It is divisible by 1,2,3,4,5,6,10,12,15,20,30, and itself.

Any element of the set of numbers of the form 60*k, where k is an integer, is evenly divisible.

The greatest common factor is 3.You can check this by looking at all of the factors of 27 and seeing if 60 is divisible by any of them, and picking the largest one.Factors of 27 : 1 , 3 , 960 is divisible by 1 and 3, and of those two 3 is the larger number.

the lowest number divisalbe by all of them is 6060/2=3060/3=2060/4=1560/5=12

60 is divisible by 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60.

They are divisible by 2, 3, 4, 5, 6, 10, 12, 15, 30 and 60 at least.

Your question is impossible to answer. Any number that is divisible by both 2 and 5 will also be divisible by 10. 30 and 60 are not divisible by 9.

No, it is divisible by 3.No, it is divisible by 3.No, it is divisible by 3.No, it is divisible by 3.

For a number to be wholly divisible by 3, 4 & 5 it must also be divisible by the Lowest (or least) Common Multiple of these numbers which is 3 x 4 x 5 = 60. Consequently, the numbers you require are multiples of 60. (ie 60, 120, 180, 240 etc)

It is divisible by 3, for example.It is divisible by 3, for example.It is divisible by 3, for example.It is divisible by 3, for example.

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