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No. Add the digits of the dividend and if that is divisible by 3 then the original number is divisible by 3; if not, its remainder when divided by 3 gives the remainder when the original number is divided by 3: 1 + 2 + 1 = 4 which gives a remainder of 1 when divided by 3, so 121 divided by 3 gives a remainder of 1. (121 = 40 x 3 + 1)
No remainder. It has the same rule as 3 for divisibility. Add them up and if that is divisible by 27 then the number is divisible by 27.
No, 83 is not divisible by 3. When a number is divisible by another number, it means that the division will result in a whole number without a remainder. In this case, when you divide 83 by 3, you get 27 with a remainder of 2, which means 83 is not divisible by 3.
n = 157 157/7 = 22 remainder 3 or (22)(7) + 3 = 157 157/49 = 3 or (49)(3) = 157
It will be 3.
No. Add the digits of the dividend and if that is divisible by 3 then the original number is divisible by 3; if not, its remainder when divided by 3 gives the remainder when the original number is divided by 3: 1 + 2 + 1 = 4 which gives a remainder of 1 when divided by 3, so 121 divided by 3 gives a remainder of 1. (121 = 40 x 3 + 1)
If the number has a remainder of 2 or 4 when divided by 6, it is an even number, so it is not prime number. 6n + 2 = 2 (3n + 1), so it is divisible by 2. 6n + 4 = 2 (3n + 2), so it is divisible by 2. If the number has a remainder of 3 when divided by 6, it is divisible by 3, so it is not a prime number. 6n + 3 = 3 (2n + 1), so it is divisible by 3. However, there are two prime numbers that do not have a remainder of 1 or 5 when divided by 6 : 2 and 3
No remainder. It has the same rule as 3 for divisibility. Add them up and if that is divisible by 27 then the number is divisible by 27.
To determine if 65483 is divisible by a certain number, you would typically divide 65483 by that number and check if the remainder is zero. 65483 divided by 2 has a remainder, so it is not divisible by 2. 65483 divided by 3 also has a remainder, so it is not divisible by 3. However, 65483 divided by 7 gives a remainder of 0, so it is divisible by 7.
No. To be divisible by 3, if the sum of the digits is divisible by 3 so is the original number, otherwise the remainder when the sum is divided by 3 is the remainder when the original number is divided by 3. 5 + 0 + 0 = 5 5 ÷ 3 = 1 r 2, so 500 ÷ 3 has remainder 2.
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No, but it will leave a remainder if divided.
To check if a number is divisible by another number, we divide. When we divide, there cannot be a remainder. For example, is 9 divisible by 3? Yes, it is because 9 divided by 3 is 3 without a remainder. How about 4? No, because when we divide 4 by 3 there is a remainder of 1. nycfunction@yahoo.com sum of the numbers in the given digits should be divisible by 3.then we can say that it is divisible by 3.example :22344 is divisible by 3.since2+2+3+4+4=15.so the given digit is divisible by 3
How about 27
No 13 is not divisible by 3 because there would be a remainder of 1 and a number that is divisible by another should have no remainder
To determine if 2421 is divisible by a certain number, we need to check if the remainder when 2421 is divided by that number is zero. For example, 2421 ÷ 3 = 807 with no remainder, so 2421 is divisible by 3. However, 2421 is not divisible by 2, as 2421 ÷ 2 = 1210 with a remainder of 1. Similarly, 2421 is not divisible by 5, as 2421 ÷ 5 = 484 with a remainder of 1.