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No. Add the digits of the dividend and if that is divisible by 3 then the original number is divisible by 3; if not, its remainder when divided by 3 gives the remainder when the original number is divided by 3: 1 + 2 + 1 = 4 which gives a remainder of 1 when divided by 3, so 121 divided by 3 gives a remainder of 1. (121 = 40 x 3 + 1)
No remainder. It has the same rule as 3 for divisibility. Add them up and if that is divisible by 27 then the number is divisible by 27.
No, 83 is not divisible by 3. When a number is divisible by another number, it means that the division will result in a whole number without a remainder. In this case, when you divide 83 by 3, you get 27 with a remainder of 2, which means 83 is not divisible by 3.
n = 157 157/7 = 22 remainder 3 or (22)(7) + 3 = 157 157/49 = 3 or (49)(3) = 157
No, 49 cannot be divided by 3 evenly. 43 divided by 3 is equal to 16⅓. A general way of knowing if a number is divisible by 3 is by finding the sum of the individual numbers that is being divided. If the sum itself is divisible by 3, then the number is likewise also divisible. For example, the problem stated is 49/3. In 49, 4+9=13. Because 13 is not evenly divisible by 3, 49 also cannot be evenly divided by 3. In another example, the problem stated is 153/3. In 153, 1+5+3=9. Because 9 is divisible by 3, 153 is also likewise divisible by 3. 153/3=51.
No. Add the digits of the dividend and if that is divisible by 3 then the original number is divisible by 3; if not, its remainder when divided by 3 gives the remainder when the original number is divided by 3: 1 + 2 + 1 = 4 which gives a remainder of 1 when divided by 3, so 121 divided by 3 gives a remainder of 1. (121 = 40 x 3 + 1)
A number that is divisible by another number has no remainder when divided by that number. For example, if a number can be evenly divided by 3, then it is considered divisible by 3. In this context, "divisible" is synonymous with "a multiple of," as it indicates that one number can be expressed as a multiple of another.
If the number has a remainder of 2 or 4 when divided by 6, it is an even number, so it is not prime number. 6n + 2 = 2 (3n + 1), so it is divisible by 2. 6n + 4 = 2 (3n + 2), so it is divisible by 2. If the number has a remainder of 3 when divided by 6, it is divisible by 3, so it is not a prime number. 6n + 3 = 3 (2n + 1), so it is divisible by 3. However, there are two prime numbers that do not have a remainder of 1 or 5 when divided by 6 : 2 and 3
To determine if 65483 is divisible by a certain number, you would typically divide 65483 by that number and check if the remainder is zero. 65483 divided by 2 has a remainder, so it is not divisible by 2. 65483 divided by 3 also has a remainder, so it is not divisible by 3. However, 65483 divided by 7 gives a remainder of 0, so it is divisible by 7.
No remainder. It has the same rule as 3 for divisibility. Add them up and if that is divisible by 27 then the number is divisible by 27.
16
No. To be divisible by 3, if the sum of the digits is divisible by 3 so is the original number, otherwise the remainder when the sum is divided by 3 is the remainder when the original number is divided by 3. 5 + 0 + 0 = 5 5 ÷ 3 = 1 r 2, so 500 ÷ 3 has remainder 2.
946
To check if a number is divisible by another number, we divide. When we divide, there cannot be a remainder. For example, is 9 divisible by 3? Yes, it is because 9 divided by 3 is 3 without a remainder. How about 4? No, because when we divide 4 by 3 there is a remainder of 1. nycfunction@yahoo.com sum of the numbers in the given digits should be divisible by 3.then we can say that it is divisible by 3.example :22344 is divisible by 3.since2+2+3+4+4=15.so the given digit is divisible by 3
No, but it will leave a remainder if divided.
To determine if 2421 is divisible by a certain number, we need to check if the remainder when 2421 is divided by that number is zero. For example, 2421 ÷ 3 = 807 with no remainder, so 2421 is divisible by 3. However, 2421 is not divisible by 2, as 2421 ÷ 2 = 1210 with a remainder of 1. Similarly, 2421 is not divisible by 5, as 2421 ÷ 5 = 484 with a remainder of 1.
How about 27