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Is it true that a number is divisible by three if the sum of the number is three?
Wiki User
∙ 2010-03-30 02:57:38
The rule of thumb is that if the sum of the digits of the number equals a number that is divisible by 3, then the number is divisible by 3.
For example,
372: 3+7+2 = 12, which is a multiple of 3 (3x4=12)
So, 3 is a factor of 372
(which is true, as 3 x 124 = 372).
124: 1+2+4 = 7, which is not a multiple of 3
So, 3 is not a factor of 124
(which is true, as 124 is not evenly divisible by 3, 124/3 = 41.33333)
Wiki User
∙ 2010-03-30 02:57:38
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If the ............. of the digits for a whole number is divisible by three then the whole number is also divisible by three?
You would fill in the blank with the word sum, which means that you add each of the digits of the number. If that sum is divisible by three then the number is divisible by 3.
Sum of three consecutive integers is divisible by three?
yes always this is true' example 1,2,3 sum is 6 and is divisible by 3
Is 10000 divisible by three?
No. If a number is divisible by three, the sum of its digits will be divisible by three. Obviously, the sum of the digits of 10000 is 1, and 1 is not divisible by 3, so 10000 is not divisible by 3.
Is this fact true A whole number is divisible by 3 if the sum of its digits is divisible by 3?
True fact.
What is a quick way to determine if 3 is a factor of a number?
If the sum of the digits of a given number is divisible by three, the number is divisible by three.
What is a number n where if the sum of the digits of the number is divisible by n, then the number itself is divisible by n?
(The assumes that "the number" in the question is not n, although if they are they same number, this is still true.) "If the sum of the digits of the number is divisible by n, then the number itself is divisible by n" is true if n is 3 or if n is 9.
The sum of 3 consective numbers is divisible by 3?
Any three consecutive integers are divisible by three because it can be shown that the sum divided by three is the middle number.
What is the divisibility rule for 3?
A number is divisible by 3 if the sum of its digits is a multiple of 3. For example, 27 = 2 + 7 = 9/3 = 3. Therefore, 27 is divisible by 3.If the sum of the digits of the number in question is divisible by three, the whole number is divisible by three.
How would you reconise a multiple of three?
if the number is a 2 or more diget number, you add up all of the numbers in the number and when you have the sum, if the sum is divisible by 3 , the whole number is divisible by three EX. 123=6, 6 is divisible by 3 so 123 is divisible by three 447=15 is divisible by 3 so 447 is divisible by 3 989=26 is *NOT* divisible by 3 so 989 is not divisible by three this truly does work for every single number
Is 153 a composite number?
It's divisible by three, since the sum of its digits is divisible by three. So it's composite.
How do we know if a number is divisible by 3?
If the sum of the digits is a multiple of three, the whole number is a multiple of three.
Is 126 divisible by three?
A number is divisible by three is the sum of its digits (here, 1+2+6=9) is divisible by 3. So, Yes.
