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The rule of thumb is that if the sum of the digits of the number equals a number that is divisible by 3, then the number is divisible by 3.

For example,

372: 3+7+2 = 12, which is a multiple of 3 (3x4=12)

So, 3 is a factor of 372

(which is true, as 3 x 124 = 372).

124: 1+2+4 = 7, which is not a multiple of 3

So, 3 is not a factor of 124

(which is true, as 124 is not evenly divisible by 3, 124/3 = 41.33333)

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Q: Is it true that a number is divisible by three if the sum of the number is three?

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You would fill in the blank with the word sum, which means that you add each of the digits of the number. If that sum is divisible by three then the number is divisible by 3.

yes always this is true' example 1,2,3 sum is 6 and is divisible by 3

No. If a number is divisible by three, the sum of its digits will be divisible by three. Obviously, the sum of the digits of 10000 is 1, and 1 is not divisible by 3, so 10000 is not divisible by 3.

True fact.

If the sum of the digits of a given number is divisible by three, the number is divisible by three.

(The assumes that "the number" in the question is not n, although if they are they same number, this is still true.) "If the sum of the digits of the number is divisible by n, then the number itself is divisible by n" is true if n is 3 or if n is 9.

Any three consecutive integers are divisible by three because it can be shown that the sum divided by three is the middle number.

A number is divisible by 3 if the sum of its digits is a multiple of 3. For example, 27 = 2 + 7 = 9/3 = 3. Therefore, 27 is divisible by 3.If the sum of the digits of the number in question is divisible by three, the whole number is divisible by three.

if the number is a 2 or more diget number, you add up all of the numbers in the number and when you have the sum, if the sum is divisible by 3 , the whole number is divisible by three EX. 123=6, 6 is divisible by 3 so 123 is divisible by three 447=15 is divisible by 3 so 447 is divisible by 3 989=26 is *NOT* divisible by 3 so 989 is not divisible by three this truly does work for every single number

It's divisible by three, since the sum of its digits is divisible by three. So it's composite.

If the sum of the digits is a multiple of three, the whole number is a multiple of three.

A number is divisible by three is the sum of its digits (here, 1+2+6=9) is divisible by 3. So, Yes.

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