Yes
102 is divisible by: 1 2 3 6 17 34 51 102.
100 is divisible by 1, 2, and 5. 1 is not itself a prime number; 101 is a prime; 102/2 =51 102/3 =34 102/17=6
Yes. Every non-zero number is divisible by itself.
A prime number is divisible only by itself - 102 is divisible by 2 and 51 so it is not a prime.A prime number is divisible only by 1 and itself.102 is a composite number because it is divisible by 2, 17, and 51 as well as by 1 and itself.Every even number (except 2) is composite.
Yes 102 is indeed divisible by 6. A simple way to find out if a number is divisible by six is the divisibility rules. For 6, Check if the number ends in a even number such as 0, 2, 4, 6, or 8. Then, add the digits of your number and check if it is any number which is a multiple of 3. For example, 102 ends in 2 1+0+2=3 102 is divisible by 6.
102 For a number to be divisible by 6, it must be divisible by both 2 and 3. 102 div by 2 = 51; 102 div by 3 = 17
A prime number is divisible only by itself - 102 is divisible by 2 and 51 so it is not a prime.
The first whole number divisible by 3 is 102 and the last one 399. Let n be the number of whole numbers between 102 and 399 102 + (n - 1)x3 = 399 (this is an arithmetic progression) Solving n, n-1 = (399 - 102)/3 = 99 n = 100 Since even whole numbers among these 100 will be divisible by 6, the number not divisible is half of 100, i.e. 50. regards, lpokbeng
Any number of the form 102*k where k is an integer.
The factors of 102 are 1, 2, 3, 6, 17, 34, 51, and 102. So it is composite with eight factors.
102.
102