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Their sum is real.

Q: Is the sum of a complex number and its conjugate a real or imaginary number?

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It is a pure imaginary number.Since (a+bi)-(a-bi) = 2bi, it is a pure imaginary number (it has no real component).

For a complex number (a + bi), its conjugate is (a - bi). If the number is graphically plotted on the Complex Plane as [a,b], where the Real number is the horizontal component and Imaginary is vertical component, the Complex Conjugate is the point which is reflected across the real (horizontal) axis.

A conjugate number refers to a complex number having both the imaginary and real parts of opposite signs and equal magnitude.

The conjugate will have equal magnitude. The angle from the real axis will be the same angle measure (but opposite direction).

No. A complex number is a number that has both a real part and an imaginary part. Technically, a pure imaginary number ... which has no real part ... is not a complex number.

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Since the imaginary portion of a real number is zero, the complex conjugate of a real number is the same number.

When a complex number is multiplied by its conjugate, the product is a real number and the imaginary number disappears.

Yes they do, complex conjugate only flips the sign of the imaginary part.

It is a pure imaginary number.Since (a+bi)-(a-bi) = 2bi, it is a pure imaginary number (it has no real component).

Aamir jamal; All real numbers are complex numbers with 0 as its imaginary part.A real number is self-conjugate. e.g;a+0i self conjugate =a-0i i=iota

For a complex number (a + bi), its conjugate is (a - bi). If the number is graphically plotted on the Complex Plane as [a,b], where the Real number is the horizontal component and Imaginary is vertical component, the Complex Conjugate is the point which is reflected across the real (horizontal) axis.

A conjugate number refers to a complex number having both the imaginary and real parts of opposite signs and equal magnitude.

Graphically, the conjugate of a complex number is its reflection on the real axis.

The conjugate will have equal magnitude. The angle from the real axis will be the same angle measure (but opposite direction).

Multiply top and bottom by the complex conjugate of the bottom complex number; this will make the bottom complex number into a real number which can then be made into fractions and simplified with the real part and the imaginary part (the multiplier of i [√-1]) of the multiplied out top number.

For any number (a + bi), its conjugate is (a - bi), so the real part stays the same, and the imaginary part is negated.For this one, conjugate of [-3 - 9i] is: -3 + 9i

Yes. If you multiply X + iY by X - iY you get X2 + Y2. The imaginary parts cancel out.