No, there are infinitely many: all the natural numbers.
only one whole number is not a natural number and it is 0
The only non-natural whole number is 0.
It is a whole number.
A whole number is one without a decimal or fraction, and a natural number is any positive integer, so this is both a whole number and an integer.
natural numbers are 1, 2, 3, 4, 5..........whole numbers are natural numbers including 0, i.e., 0, 1, 2, 3, 4, 5..........
No. The natural numbers are the counting numbers {1, 2, 3, ....} and every one of them is a whole number. 4/11 is a fraction (rational number) which is not [also a whole number], thus it cannot be a natural number.
zero
There is only one whole number in 621860 and that is 621860.
No. 1.68 is not a natural number or a whole number. "Natural" numbers are the counting numbers . . . one, two, three, four . . . 1.68 is not one of them. "Whole" numbers are the integers . . . the natural numbers, their negatives, and zero. 1.68 isn't one of those either. About all you can say for 1.68 is that it's positive, it's mixed, and it's rational.
So basically if your questions says 'What natural number has no predecessor ' it will be 1 because behind one is 0 which is a whole number but not a natural number .So the answer will be 1.
It is a whole number and an integer but, since it is only one number, it cannot be "a integers"!
The natural numbers are positive integers (whole numbers) starting from one. So, the first natural number is 1, the second natural number is 2, the third is 3, and so on.