no it is not. it is only a binomial.
x3 + 13x2 + 42x = x(x + 6)(x + 7).
It is: (x2 + 5x) (x + 8)
x(x + 9)(x + 5)
It could be x3 + 2x + 0It could be x3 + 2x + 0It could be x3 + 2x + 0It could be x3 + 2x + 0
x3 - 10x2 + 24x = x(x2 - 10x + 24) = x(x - 6)(x - 4).
x(x - 4)(x - 6)
x3 - 10x2 + 24x = x(x2 - 10x + 24) = x(x2 - 4x - 6x + 24) = x[ x(x - 4) - 6(x - 4) ] = x(x - 6)(x - 4)
x3 + x2 + 4x + 4 = (x2 + 4)(x + 1)
x3 + 4x2 + x + 4 = (x + 4)(x2 + 1)
No.
yes
x3 + x2 - 6x + 4 = (x - 1)(x2 + 2x - 4)