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What does x equal if x square equals -3?
If you want to work with real numbers, there is no answer. the square of any number, whether positive or negative, is a positive number, so x2 cannot be -3. If you accept complex numbers as a solution, the square root of minus 1 is called i (when squared, both i and -i give -1); the square root of -3 is equal to the square root of 3 times i, the square root of -4 is 2i, etc. Complex numbers are frequently used in some areas of science (electricity, quantum mechanics, and others); in other areas, it just doesn't make sense to use them. Similarly, for some problems fractional solutions, or negative solutions, may be acceptable, for others, not.
Is the square root of -4 irrational?
The square root of -4 is not irrational, it is imaginary. Irrational numbers are numbers that cannot be expressed as a fraction, like the square root of 2. Irrational numbers, however, are a subset of real numbers. The square root of -4 however, is not even a real number because no real number, when squared, gives -4. Therefore the square root of -4 is an imaginary number.In calculus, the root is expressed as 2i where iis the square root of -1.
What is the complex conjugate of -12 over 2i-6?
2i+6
How do you convert the complex number to standard form 1 plus 2i over root2 plus i?
Multiply the numerator and denominator by the complex conjugate of the denominator ... [ root(2) minus i ]. This process is called 'rationalizing the denominator'.
How do you divide complex numbers?
When dividing complex numbers you must:Write the problem in fractional formRationalize the denominator by multiplying the numerator and denominator by the conjugate of the denominator.You must remember that a complex number times its conjugate will give a real number.a complex number 2+2i. the conjugate to this is 2-i1. Multiply both together gives a real number.(2+2i)(2-2i) = 4 -4i + 4i + (-4i2) (and as i2 = -1) = 8To divide a complex number by a real number simply divide the real parts by the divisor.(8+4i)/2 = (4+2i)To divide a real number by a complex number.1. make a fraction of the expression 8/(2+2i)2. multiply by 1. express 1 as a fraction of the divisor's conjunction. 8/(2+2i)*(2-2i)/(2-2i)3. multiply numerator by numerator and denominator by denominator.(16-16i)/84. and simplify 2-2i
What is conjugation of 7-2i?
The conjugate of a complex number can be found by multiplying the imaginary part by -1, then adding the "real" part back. (-2i) * -1 = 2i, so the conjugation is 7+2i
Is the sum of two conjugate complex number a real number?
Not necessarily. It can be wholly imaginary.For example, 1 + i actually has two complex conjugates. Most schools will teach you that the complex conjugate is 1 - i. However, -1 + i is also a conjugate for 1 + i. (Their product is -1 times the product of the "normal" conjugate pair).The sum of 1 + i and -1 + i = 2i
What is the magnitude of the complex number 8 plus 2i?
8.2462 (rounded)
What is the conjugate of 7 minus 2i?
the conjugate 7-2i
If 3 - 2i is a solution to a polynomial equation is the complex conjugate 3 plus 2i also a solution yes or no?
Not necessarily, take for example the equation x^2=5-12i. Then, 3-2i satisfies the equation. However, 3+2i does not because (3+2i)^2 = 5+12i.
Can you figure out two complex numbers where neither a nor b are zero that when multiplied together become a real number?
This might be a complex number and its conjugate: (a + bi) times (a - bi). More generally, any two complex numbers such that the angle formed by one is the negative of the angle formed by the other. In other words, you can multiply the conjugate by any real constant and still get a real result: (a + bi) times (ca - cbi). Specific examples: Multiply (3 + 2i) times (3 - 2i). Multiply (3 + 2i) times (6 - 4i).
What is the conjugate of 7 - 2i?
7 + 2i
What is the conjugate of 6-2i?
8
What is the conjugate of 6 minus 2i?
6+2i
