sum of n natural number is n(n+1)/2
first 50 number sum is 50(50+1)/2 = 1275
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1, 2, 3, 4, . . . . , 49, 50. Therefore, 1275 is the sum of positive integers up to 50.
The sum of the first 50 whole numbers is 1,225.
the sum of first 50 consecutive odd numbers is 9801
The sum of the first 50 counting numbers, excluding zero, is 1,251.
Sum of first n natural numbers is (n) x (n + 1)/2 Here we have the sum = 100 x (101)/2 = 50 x 101 = 5050
s100=50(2+99) this is because a=1, d=1 and n=100. answer is 5050