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sum of n natural number is n(n+1)/2

first 50 number sum is 50(50+1)/2 = 1275

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51

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1275

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1, 2, 3, 4, . . . . , 49, 50. Therefore, 1275 is the sum of positive integers up to 50.

0.5*50*51 = 1275

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The sum of the first 50 natural numbers is 1275.

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1275

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1275

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1275

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Q: What is the sum of the first 50 natural numbers?

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The sum of the first 50 whole numbers is 1,225.

the sum of first 50 consecutive odd numbers is 9801

The sum of the first 50 counting numbers, excluding zero, is 1,251.

Sum of first n natural numbers is (n) x (n + 1)/2 Here we have the sum = 100 x (101)/2 = 50 x 101 = 5050

s100=50(2+99) this is because a=1, d=1 and n=100. answer is 5050

Related questions

The sum of the first 50 natural numbers is 1,251.

The sum of the first 50 whole numbers is 1,225.

The sum of the first 50 even numbers is 2,550.

The sum of the first 50 odd numbers is 2,500.

the sum of first 50 consecutive odd numbers is 9801

The sum of the first 50 counting numbers, excluding zero, is 1,251.

Draw a flowchart to find the sum of first 50 natural numbers.

Sum of first n natural numbers is (n) x (n + 1)/2 Here we have the sum = 100 x (101)/2 = 50 x 101 = 5050

The first 100 odd natural numbers are the number 1-201, ignoring all even numbers. If you think about this for a moment, you realize that : 1+201 = 202 3+199 = 202 5+197 = 202 etc. With this, you can pair up all of your numbers leaving you with 50 pairs, all equaling 202. Ergo: 50*202 = 10100 is your sum.

1-50 inclusive

s100=50(2+99) this is because a=1, d=1 and n=100. answer is 5050

of all the things i got is 2550