answersLogoWhite

0


Best Answer

They are the same.

User Avatar

Wiki User

9y ago
This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: Ratio of perimeters given ratio of similitude?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

If the ratio of the side lengths of two similar polygons is 31 what is the ratio of the perimeters?

Their perimeters are in the same ratio.


Two triangles are similar and have a ratio of similarity of 3 1 What is the ratio of their perimeters and the ratio of their areas?

The ratio of their perimeters will be 3:1, while the ratio of their areas will be 9:1 (i.e. 32:1)


How do scale factor and ratio of perimeters compare?

The sacle factor between two shapes is the same as the ratio of their perimeters.


What is the solution in finding the ratio of similitude for similar triangles?

I am not sure what this is?


If the ratio of the measures of corresponding sides of two similar triangles is 49 then the ratio of their perimeters is?

4.9


What is the ratio 15ft to 9ft of the perimeters?

5:3


What is the width of two similar rectangles are 45 yd and 35 yd what is the ratio of the perimeters of the areas?

The ratio of their perimeters is also 45/35 = 9/7. The ratio of their areas is (9/7)2 = 81/63


If the perimeters of two squares are in a ratio of 4 to 9 what is the areas of the two squares?

The ratio is 16 to 81.


An equilateral triangle and a square have equal perimeters what is the ratio of the area of the triangle to the area of the square?

If an equilateral triangle and a square have equal perimeters, then the ratio of the area of the triangle to the area of the square is 1:3.


What is the similarity ratio and the ratio of the perimeters of two regular octagons with areas of 18in2 and 50in2?

is it 3:5 and 3:5


What are two different size squares that the ratio of their perimeters is the same as the ratio of their areas?

Assume square A with side a; square B with side b. Perimeter of A is 4a; area of A is a2. Perimeter of B is 4b; area of B is b2. Given the ratio of the perimeters equals the ratio of the areas, then 4a/4b = a2/b2; a/b = a2/b2 By cross-multiplication we get: ab2 = a2b Dividing both sides by ab we get: b = a This tells us that squares whose ratio of their perimeters equals the ratio of their areas have equal-length sides. (Side a of Square A = side b of Square B.) This appears to show, if not prove, that there are not two different-size squares meeting the condition.


If the areas of two similar decagons are 625 sq ft and 100 sq ft what is the ratio of the perimeters of the decagons?

If lengths are in the ratio a:b, then areas are in the ratio a2:b2 since area is length x length. If areas are in the ratio c:d, then lengths are in the ration sqrt(c):sqrt(d). Areas of decagons are 625sq ft and 100 sq ft, they are in the ratio of 625:100 = 25:4 (dividing through by 25 as ratios are usually given in the smallest terms). Thus their lengths are in the ratio of sqrt(25):sqrt(4) = 5:2 As perimeter is a length, the perimeters are in the ratio of 5:2.