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What is the similarity ratio and the ratio of the perimeters of two regular octagons with areas of 18in2 and 50in2?
is it 3:5 and 3:5
Two squares are similar The ratio of a set of sides is 2 and 4 What is the ratio of their areas?
1:2
Is it true that the greater the perimeter the greater the area?
No, in general that is not true. For two similar figures it is true. But you can easily design two different figures that have the same perimeters and different areas, or the same area and different perimeters. For example, two rectangles with a different length-to-width ratio.
There are two rectangles what are the ratio of the first to the second?
I guess you mean the ratio of the areas; it depends if the 2 rectangles are "similar figures"; that is their matching sides are in the same ratio. If they are similar then the ratio of their areas is the square of the ratio of the sides.
Two triangular prisms are similar. The perimeter of each face of one prism is double the perimeter of the corresponding face of the other prism. How are the surface areas of the figures related?
The ratios of areas are the squares of the ratio of lengths (and the ratio of volumes are cubes of the ratio of lengths). As the perimeter of the second is twice the perimeter of the first, each length of the second is twice the length of the first, and so the ratio of the lengths is 1:2 Thus the ratio of the areas is 1²:2² = 1:4. Therefore the surface area of the larger prism is four times that of the smaller prism.
Two triangles are similar and have a ratio of similarity of 3 1 What is the ratio of their perimeters and the ratio of their areas?
The ratio of their perimeters will be 3:1, while the ratio of their areas will be 9:1 (i.e. 32:1)
What are two different size squares that the ratio of their perimeters is the same as the ratio of their areas?
Assume square A with side a; square B with side b. Perimeter of A is 4a; area of A is a2. Perimeter of B is 4b; area of B is b2. Given the ratio of the perimeters equals the ratio of the areas, then 4a/4b = a2/b2; a/b = a2/b2 By cross-multiplication we get: ab2 = a2b Dividing both sides by ab we get: b = a This tells us that squares whose ratio of their perimeters equals the ratio of their areas have equal-length sides. (Side a of Square A = side b of Square B.) This appears to show, if not prove, that there are not two different-size squares meeting the condition.
What is the width of two similar rectangles are 45 yd and 35 yd what is the ratio of the perimeters of the areas?
The ratio of their perimeters is also 45/35 = 9/7. The ratio of their areas is (9/7)2 = 81/63
If the ratio of the side lengths of two similar polygons is 31 what is the ratio of the perimeters?
Their perimeters are in the same ratio.
What is the similarity ratio and the ratio of the perimeters of two regular octagons with areas of 18in2 and 50in2?
is it 3:5 and 3:5
How do scale factor and ratio of perimeters compare?
The sacle factor between two shapes is the same as the ratio of their perimeters.
The ratio of the perimeters of two similar squares is 5 to 4. If the area of the smaller square is 32 Square Units what is the area of the larger square?
50
Two squares are similar The ratio of a set of sides is 2 and 4 What is the ratio of their areas?
1:2
Why would two shapes have equal areas and perimeters?
There is no particular reason. In fact, in general, two shapes will have different areas or perimeters or both.
Can two squares have the same ratio for their scale factor and the ratio of their areas?
Let a represent the scale factor of the two squares. Then it follows that the ratio of the areas is a^2. If these are equal, you get the equation a = a^2, and this is only true for a=0 or a=1. However, the only applicable value for a here is 1. In short, yes, they can, but only if both the scale factor and the ratio of the areas are equal to 1 (i.e. the squares are congruent)
If the ratio of the measures of corresponding sides of two similar triangles is 49 then the ratio of their perimeters is?
4.9
Is it true that the greater the perimeter the greater the area?
No, in general that is not true. For two similar figures it is true. But you can easily design two different figures that have the same perimeters and different areas, or the same area and different perimeters. For example, two rectangles with a different length-to-width ratio.
