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Rectangle abcd has a width of 11 while its diagonal is 18. find the area and perimeter?
Wiki User
∙ 7y ago
Using Pythagoras' theorem its length is square root of 203
Area: 11 Times Square root of 203 = 11 times sq rt 203
Perimeter: 2(11+sq rt 203) = 22+2 times sq rt 203
Wiki User
∙ 7y ago
To find the area of rectangle ABCD, you can multiply the length and the width. Since the diagonal divides the rectangle into two congruent right triangles, you can use the Pythagorean theorem to find the length of ABCD. Letting x represent the length, you can solve for x: x^2 + 11^2 = 18^2, which simplifies to x^2 = 225. Thus, x = 15. The area of the rectangle is 15 * 11 = 165 square units. To find the perimeter, you can add all four sides together: 15 + 11 + 15 + 11 = 52 units.
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