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How many solutions does the following system have x plus y equals 3 and 2x plus y equals 5?
It has 2 solutions and they are x = 2 and y = 1 which are applicable to both equations
What are the solutions to the simultaneous equations of x squared plus y squared equals 20 and 2y minus x equals 0?
The solutions are: x = 4, y = 2 and x = -4, y = -2
Y2 plus x2 65 y plus x 7?
If you mean: y^2 + x^2 = 65 and y + x = 7 then the solutions are as follows:- When y = -1 then x = 8 When y = 8 then x = -1
What is 6x equals 18 plus 9y?
That is an equation, with an infinite number of solutions. It simplifies to y = 2/3 * x - 2. Two solutions are x = 6, y = 2, and x = 9, y = 4.
How many solutions does 2x-y equals 8 and x plus y equals 1 have?
2x - y = 8 x + y = 1 These are your two equations. They will have two solutions since you have two variables. The solutions are x=3 and y=-2
What is the solution to x plus y equals -2?
There are infinitely many solutions, for example, x=-7 and y=5, because -7+5=-2
2x plus y equals 5 and 2y plus 4x equals 10?
Indeterminate: possible solutions: x = 1, y = 3; x = 2, y = 1; x = 3, y = -1 etc
What are the solutions to x squared plus xy plus y squared equals 7 and 2x plus y equals 1 with work shown?
If: 2x+y = 1 then y = 1-2x If: x^2+xy+y^2 = 7 then x^2+x(1-2x)+(1-2x)^2-7 = 0 So: x^2+x-2x^2+1-4x+4x^2-7 = 0 Collecting like terms: 3x^2-3x-6 = 0 => x^2-x-2 = 0 Solving the above quadratic equation: x = -1 or x = 3 Solutions by substitution: when x = -1 then y = 3 and when x = 2 then y = -3
How many solutions do these equations have x equals y plus 1 y equals x plus 1?
1
How many solutions are in y equals -2x y equals 3x plus 5?
There is one solution for x and one solution for y. The solution is: x = -1 ; y = 2
X plus Y equals 6 wITHOUT GRAphing does system have one solution or no solution or infinite number of solutions X plus Y equals 9?
[x + y = 6] has an infinite number of solutions.
Which 2 order pairs are solutions of y x 5?
Which 2 order pairs are solutions of y x + 5
