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Three noncollinear points ( A ), ( B ), and ( C ) determine exactly three lines: line ( AB ), line ( BC ), and line ( AC ). Each pair of points defines a unique line, and since the points are noncollinear, no two lines coincide. Thus, the total number of lines determined by points ( A ), ( B ), and ( C ) is three.
Three lines are determined by three points unless the points are all on the same line ( i.e. co-linear)
Any three non-collinear points will define a single plane. A plane is composed of an infinite number of distinct lines.
Three noncollinear points A, B, and C determine exactly three lines. Each pair of points can be connected to form a line: line AB between points A and B, line AC between points A and C, and line BC between points B and C. Thus, the total number of lines determined by points A, B, and C is three.
In classical or Euclidean plane geometry two points defines exactly one line. On a sphere two points can define infinitely many lines only one of which will represent the shortest distance between the points. On other curved surfaces, or in non-Euclidean geometries, the number of lines determined by two points can vary. Even in the Euclidean plane, two points determine infinitely many lines that are not straight!
There are 13*12/2 = 78 lines.
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4*3/2 = 6 lines.
From 8 non-collinear points, the number of straight lines that can be drawn is determined by choosing any two points to form a line. This can be calculated using the combination formula ( \binom{n}{r} ), where ( n ) is the total number of points and ( r ) is the number of points to choose. For 8 points, the calculation is ( \binom{8}{2} = \frac{8 \times 7}{2 \times 1} = 28 ). Therefore, 28 straight lines can be drawn using 8 non-collinear points.
depends on the position of the points if points are collinear, we have just only one line, the minimum number. If points are in different position (if any of the two points are not collinear) we have 21 lines (7C2), the maximum number of lines.
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