let x be the smaller number.
let x + 2 be the larger number.
4 times the smaller number is 2 more than 3 times the larger number.
in equation form, this becomes:
4x = 3 * (x+2) + 2
simplify this to get:
4x = 3x + 6 + 2 which becomes:
4x = 3x + 8
subtract 3x from both sides of this equation to get:
x = 8
44 & 45
4,6,8,10
There are no two consecutive even integers, consecutive odd integers, or consecutive integers that satisfy that relationship.
There are no such integers.
They are 6, 8, 10 and 12.
Divide the sum of the two consecutive even integers by 2: 90/2 = 45. The smaller of these integers will be one less than 45 and the larger will be one more than 45, so the two consecutive even integers will be 44 and 46.
Divide the sum of the two consecutive odd integers by 2: 156/2=78. The two consecutive odd integers will be one more and one less than 78, so the smaller will be 77 and the larger will be 79.
12 and 13.
The integers are 10 and 11.
The larger integer is 30. The smaller is 28.
x+3 and x+4 would be consecutive integers.
The product of two consecutive positive integers can be found by multiplying the smaller integer by the larger integer. If the smaller integer is represented as ( n ), then the larger integer would be ( n + 1 ). Therefore, the product of two consecutive positive integers is ( n \times (n + 1) ).