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The sum of the 1st n terms is :

N(3N-1)/2

Explanation : The sum from 1 to N of (3m-2) = 3 * sumFrom1toN(m) - sumFrom1toN(2) = 3 * (N*(N+1)/2) -2*N = N(3N-1)/2

For N=10 => 145

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Q: The 'nth term of an Arithmetic Progression is 3n-2.Find the sum of first n terms.What is the sum of first 10 terms?
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