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Q: The equation below describes a circle. What are the coordinates of the center of the circle (x - 6)2 plus (y plus 5)2 152?
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How do you find the general form equation of a circle?

There are probably several ways to approach it; one general equation for the circle is: (x - a)2 + (y - b)2 = r2 This describes a circle with center at coordinates (a, b), and with a radius of r.


How do you write the equation of a circle?

The general equation for the circle - or one of them - is: (x - a)^2 + (y - b)^2 = r^2 Where: a and b are the coordinates of the center r is the radius


Which equation describes the circle with radius 7 that is centered at the origin?

The simplest formula, in polar coordinates, is r = 7.


What equation describes the circle with radius 6 that is centered at the oridin?

The equation in Cartesian coordinates is x2 + y2 = 6 But much simpler are the polar coordinates: r = 6 and 0 ≤ q < 360 degrees.


How do you solve the circle?

The formula for the equation of a circle is (x – h)2+ (y – k)2 = r2, where (h, k) represents the coordinates of the center of the circle, and r represents the radius of the circle.


How do you find the radius and the coordinates of the center for each circle?

The answer depends on what information is available and in what form.The simplest solution is to write the equation of the circle in the following form:(x - a)^2 + (y - b)^2 = r^2Hiving done that, the coordinates of the centre are (a, b), and the circle's radius is r.


What is the equation of a circle with radius 10 and center -3 and 6?

Equation of a circle is given by: (x-a)2 + (y-b)2 = r2 Here a & b are the coordinates of the center. So, a = -3 & b = 6. And r = 10. Thus, the equation formed is (x+3)2+(y-6)2 = 102


How do you calculate the coordinates of center of a rotation?

In the algebraic equation for a circle. (x - g)^2 + (y - h)^2 = r^2 'g' & 'h' are the centre of rotation.


How do you write an equation for a circle with a center?

Equation of any circle, with any radius, and its center at any point: [ x - (x-coordinate of the center) ]2 + [ y - (y-coordinate of the center) ]2 = (radius of the circle)2


Where is the center of the circle given by the equation x plus 5 times 2 plus y - 3 times 2 equals 25 in an ordered pair?

Exactly as it's stated, that equation describes a straight line, not a circle. If you take out the phrase "times 2" from both places where it's used and replace it with "squared", then the equation describes a circle, centered at (-5, 3), with a radius of 5.


What is the equation of the circle with center 2 9 and radius 7?

depends on the equation.


What is the standard form of an equation where the poin 3-6 is on a circle whose orgin is the center?

9