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Q: The first multiple of 11 without a repeated digit?
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What is the first multiple of 11 without a repeated digit?

132 (11x12)


How many 2 digit numbers can be formed with 0 through 5 where 0 is the first digit and others can not be repeated?

-- If 'zero' is always the first digit, then we're pretty darn sure that no other digit can be repeated in the same 2-digit number, since there's only one digit left to be filled in. -- If 'zero' is always the first digit, then there are exactly six possible 2-digit numbers: 00 01 02 03 04 and 05.


What is the least 6-digit number which is divisible by 6 with no repeated digits?

0


What is the first 3 digit multiple of 11?

110


What is the first 3 digit multiple of 9?

108


The smallest 12- digit number where repeated digits are allowed?

The first digit would have to be 1, the remaining digits, zero.


Is the second number of 271 a multiple of the first?

If you mean digit, the answer is NO.


What is the sum of the product of the first 5 digit number and 5 digit multiple of 6?

The question is a bit ambiguous: "the sum of the product ... " does not seem to make sense. The first 5 digit number is 10000 the first 5 digit multiple of 6 is 10002 Their product is 100020000. I am not sure what to sum, though.


How many 5 digit numbers are there with distinct numbers?

I suspect you mean "without repeated digits", and I'll answer it that way.Here's how I would construct all the 5-digit numbers without repeated digits:The first digit can be any one of 9 (1 thru 9 but not zero). For each of these . . .The second digit can be any one of 9 (zero thru 9 but not the same as the first one). For each of these . . .The third digit can be any one of the remaining 8. For each of these . . .The fourth digit can be any one of the remaining 7. For each of these . . .The fifth digit can be any one of the remaining 6.Total number of possibilities = (9 x 9 x 8 x 7 x 6) = 27,216


How many 7-digit phone numbers can be formed if the first digit cannot be 0 and any digit can be repeated?

7


How many 4 digit palindromes are multiples of 9?

Nine. The sum of the digits must be a multiple of 9; because of the repeated digits, this is only possible if the first two digits add up to 9.


How many three digit combinations can be formed using 123456?

Assuming no repeated digits, lowest first, 20; in any order 120; Allowing repeated digits: 216