Yes. Digit total is 9 which is a multiple of 3 so it is too.
No factor of 9 has three digits. 450 is a three-digit multiple of 150 (and of 9) with a digit sum of 9.
Yes, it is. It can be determined in moments, without doing the division, by calculating the core digit of the number, which is 9. Every number with a core digit value of 9 is a multiple of 9, and therefore a multiple of 3.
No. To check if a number is a multiple of 3 add its digits together and if this sum is a multiple of 3, then so is the original number. This sum can be continued until a single digit remains; if the single digit is 3, 6 or 9 then the original number is a multiple of 3, otherwise not. 19 → 1 + 9 = 10 10 → 1 + 0 = 1 which is not 3, 6 or 9, so 19 is not a multiple of 3.
Add up the digits in a number, and if that sum is a multiple of 3, then the original number is also a multiple of 3. So 1 + 8 + 9 = 18, which if you're still not sure then 1+8=9, which is a multiple of 3. You can repetitively sum the digits until you have a result of a single digit number. If the single digit result is 3,6 or 9, then the original number is a multiple of 3. Also, if the single digit number is 9, then the number is also a multiple of 9. However, if the result is 6, then it is not necessarily a multiple of six.
Yes. Digit total is 9 which is a multiple of 3 so it is too.
All numbers divisible by 9 are divisible by 3, so you want all multiples of 9 that are 5 digit numbers. 10000 ÷ 9 = 11111/9 → first multiple of 9 that is a 5 digit number is 1112 x 9 = 10008 100000÷ 9 = 111111/9 → last multiple of 9 that is a 5 digit number is 11111 x 9 = 99999 → there are 11111 - 1112 + 1 = 10,000 five digit numbers that are divisible by 9 (and 3). I'll let you work some out (hint: multiple any number between 1112 and 11111 inclusive by 9).
No factor of 9 has three digits. 450 is a three-digit multiple of 150 (and of 9) with a digit sum of 9.
999 is a three-digit multiple of 9
Yes, it is. It can be determined in moments, without doing the division, by calculating the core digit of the number, which is 9. Every number with a core digit value of 9 is a multiple of 9, and therefore a multiple of 3.
No. To check if a number is a multiple of 3 add its digits together and if this sum is a multiple of 3, then so is the original number. This sum can be continued until a single digit remains; if the single digit is 3, 6 or 9 then the original number is a multiple of 3, otherwise not. 19 → 1 + 9 = 10 10 → 1 + 0 = 1 which is not 3, 6 or 9, so 19 is not a multiple of 3.
-3
4, 8, 12, 16, 20, 24, 28, 32, and 36 are the first 9 multiples of 4.
Add up the digits in a number, and if that sum is a multiple of 3, then the original number is also a multiple of 3. So 1 + 8 + 9 = 18, which if you're still not sure then 1+8=9, which is a multiple of 3. You can repetitively sum the digits until you have a result of a single digit number. If the single digit result is 3,6 or 9, then the original number is a multiple of 3. Also, if the single digit number is 9, then the number is also a multiple of 9. However, if the result is 6, then it is not necessarily a multiple of six.
If two and three can go into that number,then it is a multiple of six. It is a multiple of six if BOTH of the following statements are true: 1) The last digit (ones place) is 0, 2, 4, 6, or 8. 2) When you add all the digits together, you get a multiple of 3. For example, 39 is not a multiple of 6 because the last digit is 9. But, 36 is a multiple of 6 because the last digit is 6 and 3+6=9 and 9 is divisible by 3.
1 5 6 9
36