Q: The perimeter of a rectangle is 20 centimeters. The length is 6 centimeters.?

Write your answer...

30 ft

21cm3

Let the width be x: 2(length+width) = perimeter 2(20+x) = 50 40+2x = 50 2x = 50 -40 2x = 10 x = 5 centimeters Check: 5+5+20+20 = 50 centimeters

6cm. The perimeter of the rectangle has to add to 20. 4+4+6+6=20 Hope this helps ;-)

The perimeter of a rectangle measuring 20x45 centimeters is (2*20) + (2*45) = 40 + 90 = 130 cm

The perimeter of a rectangle is 2length +2 width. the width is x the length is x+4. Plug into the equation 2(x)+2 (x+4)=20 2x+2x+8=20 4x=12 x=3 The width is 3 the length is 7 (3+4) Area is length times width. 3(7)= 21. the area is 21 centimeters

20

Perimeter of rectangle: 2*(20+15) = 70m

Perimeter = 20+8+20+8 = 56 cm.....

a rectangle has a perimeter of 72m. If the length is 20 m longer than the width find its dimensions?

20 cm

Length: 4; Width: 5 or Length: 5; Width: 4

perimeter = 2 x (length + width) ⇒ length + width = perimeter ÷ 2 ⇒ length = (perimeter ÷ 2) - width So to find the length of the given rectangle, subtract the width from half the perimeter is how to do it. IF you meant "What is the length..." then: length = perimeter ÷ 2 - width = 40 ÷ 2 - 2 in = 20 - 2 in = 18 in

length + width = 20/2 = 10 length = 7cm, width = 3cm

20

20

20

The length is 20 units and the width is 10 units

the answer to number 20 is B...12

The perimeter of a rectangle = 2 x (length + width) = 2 x (12 + 8) = 2 x 20 = 40 inches

You are describing a cuboid, not a rectangle. A rectangle has only two diminutions, length and width.

30 ft.

24 meters

20 feet

20 yds