9
7
9
4,6,8,10
6 times 7 = 42 and so 7 is the larger number
In fact, they can. 2 and 3 are consecutive prime numbers.For larger numbers, one of two consecutive numbers will always be even, and therefore, not a prime.In fact, they can. 2 and 3 are consecutive prime numbers.For larger numbers, one of two consecutive numbers will always be even, and therefore, not a prime.In fact, they can. 2 and 3 are consecutive prime numbers.For larger numbers, one of two consecutive numbers will always be even, and therefore, not a prime.In fact, they can. 2 and 3 are consecutive prime numbers.For larger numbers, one of two consecutive numbers will always be even, and therefore, not a prime.
They are 6, 8, 10 and 12.
The two numbers are 9 and 11, or indeed -9 and -11. Therefore, the larger number is 11 (or -9).
In 'normal' arithmetic, there is no solution of 3 consecutive odd numbers where the product of the smaller two is 22 less than that of the larger two. For instance difference in products for 1-3-5 is 12, for 3-5-7 it is 20, and for 5-7-9 it is 28. The series steps by 8 integers for each set of 3 odd numbers investigated.
6 x 8 = 48 10 x 12 = 120 120 - 48 = 72
Two negative consecutive odd integers that have a product of 63 are -7 and -9. -7 is larger than -9. -7 is the answer.
Consecutive even numbers that sum to thirty-eight (38) are eighteen (18) and twenty (20). Twenty (20) is larger than eighteen (18).
-7