Study guides

☆☆

Q: The product of 2 consecutive odd numbers is 63What is the larger number?

Write your answer...

Submit

Still have questions?

Related questions

9

7

4,6,8,10

6 times 7 = 42 and so 7 is the larger number

In fact, they can. 2 and 3 are consecutive prime numbers.For larger numbers, one of two consecutive numbers will always be even, and therefore, not a prime.In fact, they can. 2 and 3 are consecutive prime numbers.For larger numbers, one of two consecutive numbers will always be even, and therefore, not a prime.In fact, they can. 2 and 3 are consecutive prime numbers.For larger numbers, one of two consecutive numbers will always be even, and therefore, not a prime.In fact, they can. 2 and 3 are consecutive prime numbers.For larger numbers, one of two consecutive numbers will always be even, and therefore, not a prime.

They are 6, 8, 10 and 12.

The two numbers are 9 and 11, or indeed -9 and -11. Therefore, the larger number is 11 (or -9).

In 'normal' arithmetic, there is no solution of 3 consecutive odd numbers where the product of the smaller two is 22 less than that of the larger two. For instance difference in products for 1-3-5 is 12, for 3-5-7 it is 20, and for 5-7-9 it is 28. The series steps by 8 integers for each set of 3 odd numbers investigated.

6 x 8 = 48 10 x 12 = 120 120 - 48 = 72

Two negative consecutive odd integers that have a product of 63 are -7 and -9. -7 is larger than -9. -7 is the answer.

-7

Consecutive even numbers that sum to thirty-eight (38) are eighteen (18) and twenty (20). Twenty (20) is larger than eighteen (18).

9

"Two consecutive numbers" implies that these are whole numbers. Consecutive whole numbers have different parity - that is to say that one is odd and the other even, which means that their sum must be odd. Since 38 is even the problem has no solution.

The two numbers are 3 and 5 and so 5 is the larger number

It is 20 because 18+20 = 38

6,8,10,12

five

You can solve this in two ways.1) Trial and error. That is, try multiplying two consecutive integers; if the product is too large, try smaller integers; if the product is too small, try larger consecutive integers. 2) Call the two consecutive integers "n" and "n+1", and solve the equation: n(n+1)=210

"Either" is used for two. I'll assume that you mean "larger than ANY of them". The following applies to ANY real numbers.For TWO numbers, the product is larger than either of them if both numbers are greater than one. For THREE numbers, the product is larger than any of them if the two numbers OTHER than the largest number have a product greater than one. For example: 0.5, 3, 5 The largest number here is 5; the product of the OTHER two is 0.5 x 3 = 1.5. Or here is an example with integers: -5, -3, 10 The product of the "other two" numbers is 15, which is larger than one - so the product of all three is larger than the largest number (and therefore, larger than ANY of them). Another example: -5, 1, 10 The product of the two numbers OTHER than the largest is -5 x 1 = -5; since this is NOT greater than 1, the product of all three is NOT greater than any of the numbers. This reasoning can be extended to four or more numbers. For 4 numbers: If the product of all three numbers OTHER than the largest one is GREATER than one, then the product of ALL FOUR numbers is greater than ANY of them.

-1

4,6,8,10ok, that's kool, now what the hell is the answer to this mind blower?!?!The square of 9 more than a number is equal to 9 more than the square of the number What is the number? the answer is 10,8,6 and 4

44 & 45

The four even integers are 6, 8, 10, 12. 6 x 8 = 48 10 x 12 = 120 120 - 48 = 72

1 and 2 1 + 2 = 3 1 x 2 = 2