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In 'normal' arithmetic, there is no solution of 3 consecutive odd numbers where the product of the smaller two is 22 less than that of the larger two. For instance difference in products for 1-3-5 is 12, for 3-5-7 it is 20, and for 5-7-9 it is 28. The series steps by 8 integers for each set of 3 odd numbers investigated.

Q: Find 3 consecutive odd numbers where the product of the two smaller numbers is 22 less than the product of the two larger numbers?

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4,6,8,10

The four even integers are 4, 6, 8, and 10. 10 x 8 = 80 6 x 4 = 24 80 - 24 = 56

The larger integer is 30. The smaller is 28.

Let the smaller be n, then the larger is n+1; and: n + 4(n+1) = 59 → n + 4n + 4 = 59 → 5n = 55 → n = 11 → the two consecutive integers are 11 and 12.

Generally yes, but not in all cases. The largest prime number has over 22 million digits but only two factors whereas 60 has six times as many factors.

Related questions

4,6,8,10

They are 6, 8, 10 and 12.

9

7

9

6 x 8 = 48 10 x 12 = 120 120 - 48 = 72

6 times 7 = 42 and so 7 is the larger number

-1

In fact, they can. 2 and 3 are consecutive prime numbers.For larger numbers, one of two consecutive numbers will always be even, and therefore, not a prime.In fact, they can. 2 and 3 are consecutive prime numbers.For larger numbers, one of two consecutive numbers will always be even, and therefore, not a prime.In fact, they can. 2 and 3 are consecutive prime numbers.For larger numbers, one of two consecutive numbers will always be even, and therefore, not a prime.In fact, they can. 2 and 3 are consecutive prime numbers.For larger numbers, one of two consecutive numbers will always be even, and therefore, not a prime.

Negative Numbers.

The larger of two numbers is 8 more than 4 times the smaller if the larger number is increased by four times the smaller the result is 40. From this statement, we can calculate the values of the numbers where you get the value of the larger number to be 24 and that of the smaller number to be 4.

44 & 45