Q: The sum of 3 consecutive intergral numbers is 117. what is the numbers?

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Let the smallest number be x. Then the others are x+1, x+2 and x+3 and x + (x+1) + (x+2) + (x+3) = 474 iff 4x = 468 iff x = 117, So the consecutive whole numbers 117, 118, 119 and 120 sum to 474.

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