The square roots of 117 are irrational numbers and so are not two integers - consecutive or otherwise.
The numbers are 38, 39, and 40.
37 39 41
The numbers are 37, 39 and 41.
The first ten consecutive composite positive integers are: 114 115 116 117 118 119 120 121 122 123
If you mean two consecutive odd numbers then they are 117 and 119
The square roots of 117 are irrational numbers and so are not two integers - consecutive or otherwise.
The numbers are 38, 39, and 40.
37 39 41
The numbers are 37, 39 and 41.
117/3 = 39, so the three consective odd integers whose sum is 117 are 37, 39, and 41.
The first ten consecutive composite positive integers are: 114 115 116 117 118 119 120 121 122 123
117
Let the smallest number be x. Then the others are x+1, x+2 and x+3 and x + (x+1) + (x+2) + (x+3) = 474 iff 4x = 468 iff x = 117, So the consecutive whole numbers 117, 118, 119 and 120 sum to 474.
Three consecutive integers whose sum is 117 are 38, 39, and 40. N + (N+1) + (N+2) = 117 3N + 3 = 117 3N = 114 N = 38
9 and 6 9-6 = 3 92+62 = 117
117, 118 and 119.