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The ten's digit of a two-digit number is 3 more than the units' digit The number is 8 more than six times the sum of the digits Find the number?
Wiki User
∙ 14y ago
Let x be the unknown number and let y be the ten's digit,
then x = 10y + y - 3 = 11y - 3,
and x = 8 + 6(y + y - 3) = 8 + 6(2y - 3) = 8 + 12y - 18 = 12y -10,
therefore 12y - 10 = 11y - 3.
Subtracting 11y and adding 10 to each side, y = 7.
Since the ten's digit is 7, the unit's digit must be 4, and the number is 74.
Wiki User
∙ 14y ago
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