Let the width be x-12 and the length be x:
2(x-12+x) = 52
2x-24+2x = 52
2x+2x = 52+24
4x = 76
Divide both sides by 4 to determine the value of x:
x = 19
Therefore: width = 7 cm and the length = 19 cm
a rectangle had a perimeter of 48 and the longest side is 15 find the lenght of a shorter side
7 x 19 cm
The perimeter of a rectangle is twice the sum of the width and length: perimeter = 2 x (4.6in + 12.1 in) = 33.4 in
If the shape is a rectangle, then Perimeter = 2(Length + Width) So Width = Perimeter/2 - Length
2(length + height)= perimeter
The perimeter of a rectangle is not sufficient to determine its length.
a rectangle had a perimeter of 48 and the longest side is 15 find the lenght of a shorter side
Perimeter is Length + width x 2 or Length + length + width + width. This is perimeter for any shape including a rectangle. Perimeter of a rectangle is all sides added together for a rectangle.
The length round a rectangle is the perimeter.
The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.
The perimeter of a rectangle whose length is 5cm wit a width of 6cm is 22cm
22+27+22+27
All that can be said for sure is that length + width = 56. The rectangle could be 2 x 28, 4 x 14, 7 x 8 and those are only the whole-number dimensions...
the length of a rectangle is 5 more then the width. Find the perimeter and the area of the rectangle
no No. You need to know the length of a rectangle's sides in order to calculate the perimeter.
Perimeter of rectangle = 2 x (length + width) = 2 x (1.6 + 0.8) = 2 x 2.4 = 4.8 meters
shorter side = 10 longer side = 19