Each coin can come out either heads (H) or tales (T). Since you're tossing four coins at once, I'm assuming there is no sense of order to be accounted for. In that case, the possible outcomes are the following:
HHHH
HHHT
HHTT
HTTT
TTTT
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We use three coins (quarter, nickel, dime) each are flipped only once. We get 8 possible outcomes (or four outcomes as an alternative).
Let's call one coin A and the other B. omes The possible outcomes for the coins are; A heads and B tails, A tails and B heads, A and B heads, A and B tails. That's four outcomes. The possible outcomes for a single die (as in dice) are six since a die has six faces, So four times six is twenty four possible outcomes.
1,296
Probability is defined as the number of ways an outcome can occur divided by the number of possible outcomes. For the coins, there are 4 outcomes (HH, HT, TH, TT). On the cube, there are 6 possible outcomes. The total number of outcomes is then 4*6 = 24. Since there is only 1 way to obtain HH, look at the cube outcomes. With the HH outcome, the cube would need to fall on a 4. So, there is only 1 way a HH4 can occur. Therefore the probability of getting 2 heads and a four is 1/24 or 0.04167.
Assuming the variable of interest is the face on top: H (= heads) or T (= tails), then they are the four possible outcomes: HH, HT, TH and TT.