12-5(6-3x)2(6-x)-8x = -30x^2 + 232x -348
3x+56 = 2x+4 3x-2x = 4-56 x = -52
3X+70-7*18=0 3X+70-126=0 3X-56=0 3X=56 x=56/3 or 18.6667
56
X= 20.6666666666667
First, subtract 3x from each side of the equation. Then, divide each side of the equation by 7 .
3x + 7 = 56 - 4xAdd 4x to each side of the equation:7x + 7 = 56Subtract 7 from each side:7x = 49Divide each side by 7:x = 7
Suppose the first number is x Then the second is 3x - 8 Their sum is x + 3x - 8 = 4x - 8 = 56 So 4x = 64 and so x = 16 Then the second number is 3x - 8 = 40 The numbers are 16 and 40.
3x + 5y = 56 or 5p - 4x2 = 436p2 + 2345 - 34x
2x-10+3x-10 = 90 5x = 110 x = 22 degrees angles are 34 and 56 degrees
Let's call one of the numbers "x". Since the other number is 3 times as large as the first number, we can call it "3x". The problem states that the sum of these two numbers is 56, so we can write the equation: x + 3x = 56. Simplifying this equation gives us 4x = 56. Dividing both sides by 4 gives us x = 14. Therefore, the two numbers are 14 and 42.
If you mean: y-5 = -3(x-17) then y = -3x+56 whereas -3 is the slope and 56 is the y intercept
3x + 3x + 3x = 3* (3x) = 9x