14 x 3 = 42 + 14 = 56
Let's call one of the numbers "x". Since the other number is 3 times as large as the first number, we can call it "3x". The problem states that the sum of these two numbers is 56, so we can write the equation: x + 3x = 56. Simplifying this equation gives us 4x = 56. Dividing both sides by 4 gives us x = 14. Therefore, the two numbers are 14 and 42.
1st number=12 2nd number=24
The answer is X-13 + Y- 52 = Sum 65
20 and 5
by finding what times what = the numbers
Times the given numbers together
1st number=12 2nd number=24
The answer is X-13 + Y- 52 = Sum 65
The numbers are 21 and 63.
Let unknown numbers be 2x and x: 2x+x = 24 3x = 24 x = 8 Therefore the two numbers are 8 and 16
Why don't you try squaring some numbers? You should quickly find the answer. If the square of your number is too large, try a smaller one; if it is too small, try a larger one.
The sum of the numbers is 240. If one number is 5 times as big as the other then 240 must be divided by 6. 240/6 = 40. The smaller number must be this while the larger number is 5 times the size. Small number = 40 Larger number = 40 * 5 = 200
If the higher is 3 times the lower, the difference must be twice the lower so the numbers are 8 and 24.
One numbers 3 times another number.the difference between the numbers 10. Find the numbers.
Since one number is 3 times the other, I'd divide 84 by 4 and get 21. This is the lower number so the other must be 63.
20 and 5
Total of the numbers divided by the numbers of times the figures appear
its easy.. just compare all the numbers you will find the largets and the smallest one.