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What -1 -4x 2 2x x?

Updated: 4/28/2022
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10y ago

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A list of algebraic terms.

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10y ago
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4y ago

X=5

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Q: What -1 -4x 2 2x x?
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2x plus 2 equals 4x-1?

2x + 2 = 4x -1 2x = 3 x = 1.5


4x x to second power - 4x plus 3 equals 0?

Given, 4x2 - 4x + 3 = 0; then, 4x2 - 4x + 1 = (2x - 1)2 = -2, 2x - 1 = √-2 = ±i√2, and 2x = 1 ± i√2; therefore, x = ½(1 ± i√2).


What is 1-2x-5 equals 4x plus 2?

If: 1-2x-5 = 4x+2 Then: -2x-4x = 2-1+5 And: -6x = 6 So: x = -1


What the Anserw to 4x plus 1 equals 2x plus 5?

4x + 1 = 2x + 5 4x + 1 - 2x = 2x + 5 - 2x 2x + 1 = 5 2x + 1 - 1 = 5 - 1 2x = 4 2x/2 = 4/2 x = 2


What are the factors of 16x?

16x2-8x+1 16: -4*-4=16 -4+-4=-816x2-4x-4x+1|..........|..|.....||..........|..|......1|..........|...2*2x|.........2*2x2*2*2*2xx4x(4x-1)+1(4x-1)Answer: (4x-1)(4x+1)


How do you solve 2x-5 equals 4x-1?

you want to put all of the 'x' on one side and all of the numbers on the other side 2x-5=4x-1 2x-5 (-2x +1) = 4x -1 (-2x + 1) -4 = 2x then divide by 2 x=-2


How do you solve 2x equals 4x plus 1?

2x = 4x +1 2x-4x = 1 -2x = 1 x = - 1/2 check Leftside = 2 (- 1/2) = -1 Right side = 4 (- 1/2) +1 = -2 + 1 = 1 - 2 = -1 LS = RS therefore x = - 1/2


What are the points of intersection of the equations x2 -xy -y2 equals -11 and 2x plus y equals 1?

If: 2x+y = 1 then y = 1-2x and y^2 = (1-2x)^2 which is 1-4x+4x^2 If: x^2 -xy -y^2 = -11 then x^2 -x(1-2x) -(1-4x+4x^2) = -11 So it follows: x^2 -x +2x^2 -1 +4x -4x^2 +11 = 0 Collecting like terms: -x^2 +3x +10 = 0 Factorizing the above: (x-5)(-x-2) = 0 meaning x = 5 or -2 Points of intersection by substitution are at: (5, -9) and (-2, 5)


Factor 4x squared plus 8x plus 4?

4x2 + 8x + 4 = 4 (x2 + 2x + 1) = 4 (x + 1)2


2x2 5x -2?

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What must be subtracted from 4x power 4 so that the result is exactly divisible by 2x power 2 plus x-1?

NOT CALCULUS. Use long division. 2x2 + x - 1(4x^4) 2x^2 goes into 4x^4 2x^2 times. The remainder will then be (2x^2*(x-1)). This result(2x^3 - 2x^2) is what need to be subtracted from 4x^4 to make it exactly divisible


What are the points of contact between the equations of x2 plus xy plus y2 equals 7 and 2x plus y equals 1?

If: 2x+y = 1 then y = 1-2x If: y^2 = (1-2x)^2 then y^2 = 1-4x+4x^2 If: x^2 +xy +y^2 =7 then x^2 +x(1-2x) +1-4x+4x^2 = 7 So it follows: x^2 +x-2x^2 +1-4x+4x^2 -7 = 0 Collecting like terms: 3x^2 -3x -6 = 0 Dividing all terms by 3: x^2 -x -2 = 0 Factorizing the above: (x+1)(x-2) = 0 meaning x = 2 or -1 By substitution points of contact are made at: (2, -3) and (-1, 3)