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What are the points of contact between the equations of x2 plus xy plus y2 equals 7 and 2x plus y equals 1?
Wiki User
∙ 6y ago
If: 2x+y = 1 then y = 1-2x
If: y^2 = (1-2x)^2 then y^2 = 1-4x+4x^2
If: x^2 +xy +y^2 =7 then x^2 +x(1-2x) +1-4x+4x^2 = 7
So it follows: x^2 +x-2x^2 +1-4x+4x^2 -7 = 0
Collecting like terms: 3x^2 -3x -6 = 0
Dividing all terms by 3: x^2 -x -2 = 0
Factorizing the above: (x+1)(x-2) = 0 meaning x = 2 or -1
By substitution points of contact are made at: (2, -3) and (-1, 3)
Wiki User
∙ 6y ago
Wiki User
∙ 6y agoThey are (-1, 2) and (3, -3).
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What are the points of intersection between the equations of 2x plus y equals 5 and x2 -y2 equals 3?
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What are the points of intersection between the equations of 3x -5y equals 16 and xy equals 7?
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What are the point for the equations 9x-10y equals 1 and 10y equals x-1?
The points are: x = 0 and y = -1/10.
What are the points of intersection between the line x -y equals 2 and the curve x2 -4y2 equals 5?
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What are the coordinates for x2 plus y2 equals 185 and x plus y equals 17?
We believe that those equations have no real solutions, and that their graphs therefore have no points of intersection.
What are the points of contact between the line 3x -2y equals 1 and the curve 3x squared -2y squared plus 5 equals 0?
Equations: 3x-2y = 1 and 3x^2 -2y^2 +5 = 0 By combining the equations into one single quadratic equation and solving it the points of contact are made at (3, 4) and (-1, -2)
What are the points of intersection between the equations of 2x plus y equals 5 and x2 -y2 equals 3?
It works out that the points of intersection between the equations of 2x+5 = 5 and x^2 -y^2 = 3 are at: (14/3, -13/3) and (2, 1)
What are the points of intersection between the equations of 3x -5y equals 16 and xy equals 7?
If 3x -5y = 16 and xy = 7 then by combining both equations into a single quadratic equation and solving it then the points of intersection are at (-5/3, -21/5) and (7, 1)
What are the points of contact when the line 2x plus 5y equals 4 transverses the curve y squared equals x plus 4?
If 2x+5y = 4 and y^2 = x+4 then by combining the equations into a single quadratic equation and solving it the points of contact are made at (12, -4) and (-7/2, 3/2)
Where are the points of intersection of the equations 4y squared -3x squared equals 1 and x -2y equals 1?
The points of intersection of the equations 4y^2 -3x^2 = 1 and x -2 = 1 are at (0, -1/2) and (-1, -1)
What are the point for the equations 9x-10y equals 1 and 10y equals x-1?
The points are: x = 0 and y = -1/10.
What are the points of intersection between the line x -y equals 2 and the curve x2 -4y2 equals 5?
Equations: x -y = 2 and x^2 -4y^2 = 5 By combining the equations into a single quadratic equation in terms of y and solving it: y = 1/3 or y = 1 By means of substitution the points of intersection are at: (7/3, 1/3) and (3, 1)
What are the coordinates for x2 plus y2 equals 185 and x plus y equals 17?
We believe that those equations have no real solutions, and that their graphs therefore have no points of intersection.
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What is the solution of the system 2x plus 3y equals 2 and 4x plus 6y equals 4?
That system of equations has no solution. When the two equations are graphed, they turn out to be the same straight line, so there's no such thing as a single point where the two lines intersect. There are an infinite number of points that satisfy both equations.
What pair of pont both lie on the line whose equations is 3x-y equals 2?
No pairs of points are given so the question cannot be understood
