' 1 ' is their only common factor.
The number that is between 40 and 50 and is divisible by both 3 and 5 is 45. To determine if a number is divisible by both 3 and 5, you must ensure it is divisible by both 3 and 5 without leaving a remainder. In this case, 45 meets this criteria as it is divisible by both 3 (45 ÷ 3 = 15) and 5 (45 ÷ 5 = 9).
Both are divisible by 3 and 5 12/3 = 4 12/5 = 2.4 601848/3 = 200616 601848/5 = 40123.2 However both are only divisible by 3 with no remainder.
A number that is divisible by 15 is divisible both by 5 and 3 A number is divisible by 5 if it ends with 0 or 5 A number is divisible by 3 if the sum of its digits is divisible by 3 e.g. 4035 is divisible by 15 as it ends with a 5 and 4+0+3+5=12 which is divisible by 3
No. Both are divisible by 5.No. Both are divisible by 5.No. Both are divisible by 5.No. Both are divisible by 5.
15 is the smallest number divisible by both 3 and 5
Yes, it is divisible by both. 355 / 3 = 118.3333333333333 355 / 5 = 71
15 is divisible by 3 and 5, because 15/3=5, and 15/5=3.
Since both 3 and 5 are prime numbers, only numbers that are multiples of its product are the numbers that are divisible by both. 15 is the LCM of 3 and 5 and hence all multiples of 15 are divisible by both 3 and 5
True. Since 615 ends in 5, it is divisible by 5. Since the sum 12, of the digits of 615, is divisible evenly by 3, 615 is divisible by 3.
15
NO … it is divisible by both 3 and 5
Well, let's take a moment to look at this question. To see if a number is divisible by 3, you can add up the digits and see if that sum is divisible by 3. For 780, 7 + 8 + 0 = 15, which is divisible by 3. But for 320, 3 + 2 + 0 = 5, which is not divisible by 3. So, 780 is divisible by 3. Now, to check if a number is divisible by 5, you can see if the last digit is 0 or 5. In this case, 780 ends in 0, so it's divisible by 5. However, 320 does not end in 0 or 5, so it's not divisible by 5. So, 780 is divisible by both 3 and 5, while 320 is only divisible by 5.