I'm sorry what i was meaning what r all the 4 number combinations that can be made with 3 numbers.
Ie. 1111,1112,1113,1121,1122,1123,1131,1132,1133, etc.
In that case, we can think of it this way
For the first one, there is 3 possibilities, 1, 2, 3. For each one of them, the second one also have three possibilities, 1, 2, 3. Since there is three for every different first number, there is 9 possibilities for just the first two.
Hope you see the pattern, for all 4, it would be 3 x 3 x 3 x 3 which is 81 different possibilities.
87400 combinations
Possible 5 digit combinations using 5 digits only 1 time is 5! or 5*4*3*2*1 or 120. Using 5 digits where numbers can be used 5 times is 55 or 3125.
The answer is five factoral (5!) which is 120.
You can represent values using variables. This can only be done with whole numbers.
To calculate the number of possible combinations for the number 24680 using each number only once, we can use the formula for permutations. There are 5 numbers to arrange, so the number of permutations is 5! (5 factorial), which is equal to 5 x 4 x 3 x 2 x 1 = 120. Therefore, there are 120 possible combinations for the number 24680 using each number only once.
They are only visible if you can find them by using algebra.
Private variables can only be accessed from outside of a class by using any public function of that same class. Or this can be accomplished by using Friend functions.
There are only five combinations: 1234, 1235, 1245, 1345 and 2345.
As the number has to start with 15, we have only 3 remaining digits to work with. There are 3 possible options for the first digit. Then out of each of these, 2 possible options for the second digit, and one option for the last. This means that in total there are 3x2x1 (6) possible combinations. These are: 15234 15243 15324 15342 15423 15432
Renaming runtime variables is only possible in languages that support dynamic variables. Statically typed languages like Java do not support dynamic variables. However, there's nothing to stop you using a map to associate strings with values at runtime.
When selecting 7 items out of 7, there is only 1 possible combination.
There are only six combinations using you rule. They are:- 235, 237, 325, 327, 723 and 725