answersLogoWhite

0

The answer is five factoral (5!) which is 120.

User Avatar

Wiki User

14y ago

What else can I help you with?

Related Questions

What is the number of possible combinations using 7 digits?

128


What are the 5-number combinations not using any number twice?

There are infinitely many numbers and so infinitely many possible combinations.


What possible combinations using 4 character A-Z?

140 possible combinations


How many symbols can you make with a 7 LED grid?

In a 7 segment display, the symbols can be created using a selected number of segments where each segment is treated as a different element.When 1 segment is used, the possible positions are 7because it can be any of the 7 segments (7C1=7).When 2 segments are used, the number of possible combinations are 7C2=21.When 3 segments are used, the number of possible combinations are 7C3=35When 4 segments are used, the number of possible combinations are 7C4=35When 5 segments are used, the number of possible combinations are 7C5=21When 6 segments are used, the number of possible combinations are 7C6=7When 7 segments are used, the number of possible combinations are 7C7=1Adding the combinations, 7+21+35+21+7+1=127Therefore, 127 symbols can be made using a 7 segment display!


How many two digit number combinations can you get using the number 1234 without repeating a digit?

There are twelve possible solutions using the rule you stated.


How many possible combinations is there for 24680 using each number only once?

To calculate the number of possible combinations for the number 24680 using each number only once, we can use the formula for permutations. There are 5 numbers to arrange, so the number of permutations is 5! (5 factorial), which is equal to 5 x 4 x 3 x 2 x 1 = 120. Therefore, there are 120 possible combinations for the number 24680 using each number only once.


How many possible unique alpha numeric combinations are there using all letters for 4 characters?

im assuming that any charcter can be a number or a letter: (24letters*10 possible numbers)^(4 digits)= 3317760000 possible combinations.


Using 4 digits what is the total number of combinations for a 4 digit lock code?

If the digits can repeat, then there are 256 possible combinations. If they can't repeat, then there are 24 possibilities.


How many possible 4 digit combinations are there using 0-9 with no duplicates?

There are 5,040 combinations.


How many 9 letter combinations using 26 alphabet letters?

3,124,550 possible combinations


How many possible combinations could be constructed using 3 letters and 3 numbers for a license plate?

To calculate the total number of possible combinations for a license plate using 3 letters and 3 numbers, we need to multiply the number of options for each character position. For letters, there are 26 options (A-Z), and for numbers, there are 10 options (0-9). Therefore, the total number of combinations can be calculated as 26 (letters) * 26 (letters) * 26 (letters) * 10 (numbers) * 10 (numbers) * 10 (numbers) = 17,576,000 possible combinations.


How many possible 4 number combinations can you get using numbers 0-9?

0000-9999 (10x10x10x10 or 104) = 10,000 possible combinations allowing for repeated digits. If you are not able to repeat digits then it's 10 x 9 x 8 x 7 or 5,040 possible combinations without repeated digits.