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What are all the possible ways of making a 4 digit code formed by the numbers 0 1 2 3 4 5 6 7 8 9?
Wiki User
∙ 11y ago
If the code has to be four different digits the there are 10 x 9 x 8 x 7/ 4 x 3 x 2 ie 210 possibilites.
If repeated digits are permitted then there are 10 to the fourth ie 10000 possibilities, as each part of the code can be any of the 10 digits.
Wiki User
∙ 11y ago
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How many different 2 digit numbers can be formed from the digits 2 6 7 and 8?
Without repeats there are 4 × 3 = 12 possible 2 digit numbers. With repeats there are 4 × 4 = 16 possible 2 digit numbers.
How many 3-digit numbers can be formed using 0123456789 when repetition is not allowed?
-123456786
How many 3 digit even numbers can be formed by using numbers 01234?
Assuming leading zeros are not permitted, then: If repeats are not allowed there are 30 possible numbers. If repeats are allowed there are 60 possible numbers.
How many two digit numbers can be formed from the digits 7341 if none of the digit can be repeated?
There are twelve possible solutions using the rule you stated... 13,14,17,31,34,37,41,43,47,71,73 & 74
How many positive integers less than 100 can be written using the digits 3 and 4 and 5 and 6?
If two digit number can have a repeated digit (eg 44) then there are 20 possible numbers, otherwise there are 16 possible numbers: There are 4 single digit numbers; With repeats allowed there are a further 4 x 4 = 16 two digit numbers making a total of 20; Without repeats allowed there are a further 4 x 3 = 12 two digit numbers making a total of 16.
How many different 2 digit numbers can be formed from the digits 2 6 7 and 8?
Without repeats there are 4 × 3 = 12 possible 2 digit numbers. With repeats there are 4 × 4 = 16 possible 2 digit numbers.
How many 4 digit numbers can be formed from the digits 12345?
The first digit can have 5 possible numbers, the second digit can have 4, the third 3, the fourth 2. 5
How many 3 digit numbers can be formed from 6 single digit numbers if repeats are allowed?
if the repetition is allowed the there is 6*6*6 possible ways = 216
How many 3-digit numbers can be formed using 0123456789 when repetition is not allowed?
-123456786
How many 3 digit even numbers can be formed by using numbers 01234?
Assuming leading zeros are not permitted, then: If repeats are not allowed there are 30 possible numbers. If repeats are allowed there are 60 possible numbers.
What is the largest possible product of three 3 digit numbers all of whose digits are different?
Forming three three digit numbers that use the numbers 1-9 without repeating, the highest product possible is 611,721,516. This is formed from the numbers 941, 852, and 763.
What is the least possible sum of two 4-digit numbers?
what is the least possible sum of two 4-digit numbers?what is the least possible sum of two 4-digit numbers?
How many two digit numbers can be formed from the digits 7341 if none of the digit can be repeated?
There are twelve possible solutions using the rule you stated... 13,14,17,31,34,37,41,43,47,71,73 & 74
How many positive integers less than 100 can be written using the digits 3 and 4 and 5 and 6?
If two digit number can have a repeated digit (eg 44) then there are 20 possible numbers, otherwise there are 16 possible numbers: There are 4 single digit numbers; With repeats allowed there are a further 4 x 4 = 16 two digit numbers making a total of 20; Without repeats allowed there are a further 4 x 3 = 12 two digit numbers making a total of 16.
How many 3 digit counting numbers are not multiples of 5?
There are 720 of them. The three digit counting numbers are 100-999. All multiples of 5 have their last digit as 0 or 5. There are 9 possible numbers {1-9} for the first digit, There are 10 possible numbers {0-9} for each of the first digits, There are 8 possible numbers {1-4, 6-9} for each of the first two digits, Making 9 x 10 x 8 = 720 possible 3 digit counting numbers not multiples of 5.
How many four digits numbers can be formed using 0123456789?
Assuming that the first digit of the 4 digit number cannot be 0, then there are 9 possible digits for the first of the four. Also assuming that each digit does not need to be unique, then the next three digits of the four can have 10 possible for each. That results in 9x10x10x10 = 9000 possible 4 digit numbers. If, however, you can not use the same number twice in completing the 4 digit number, and the first digit cannot be 0, then the result is 9x9x8x7 = 4536 possible 4 digit numbers. If the 4 digit number can start with 0, then there are 10,000 possible 4 digit numbers. If the 4 digit number can start with 0, and you cannot use any number twice, then the result is 10x9x8x7 = 5040 possilbe 4 digit numbers.
How many four digit numbers can be formed using all digits if same digit on four place is not allowed example 5555 is not allowed?
Total possible 4-digit numbers= 1000, 1001,...,9999 = 9000 Total with same digit numbers = 1111,2222,...,9999 = 9 9000 - 9 = 8991
