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Q: What are 4 consecutive integers whose sum equals 114?

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27 + 28 + 29 + 30 = 114

118

The integers are 37, 38 and 39.

The integers are 27, 28, 29 and 30.

The consecutive odd integers for 114 are 37, 38 and 39.

27 28 29 30

117

The numbers are 27, 28, 29 and 30.

27 + 28 + 29 + 30 = 114

Three consecutive integers whose sum is 117 are 38, 39, and 40. N + (N+1) + (N+2) = 117 3N + 3 = 117 3N = 114 N = 38

27, 28, 29 and 30.

27, 28, 29 and 30

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